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Papessa [141]
2 years ago
6

Mrs. Ronilo had her students make a stem-and-leaf plot of the heights of all of the students in the class. The mean was 55. Dave

was absent the day they did this, and he is 57 inches tall. How does adding him into the data change the measures of central tendency?
Mathematics
2 answers:
shutvik [7]2 years ago
8 0
Given that the mean is 55 inches  and Dave is 57 inches, he would have increased the mean of the height in the stem-and-leaf plot that the students were making. This is however is also dependent upon the central tendency that was used, in this case the central tendency is mean or average. 
Nookie1986 [14]2 years ago
7 0

Answer:

mean is increased

Step-by-step explanation:

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Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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Answer:31) The Coca-Cola Company reported that the mean per capita annual sales of its beverages in the United Sates was 423 eight-ounce servings. Suppose you are curious whether the consumption of Coca-Cola beverages is higher in Atlanta. A sample of 36 individuals from the Atlanta area showed a sample mean annual consumption of 460.4 eight ounce servings with a standard deviation of s=101.9 ounces. Using a=.05, do the sample results support the conclusion that mean annual consumption of Coca-Cola beverage products is higher in Atlanta

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Answer:

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Step-by-step explanation:

The distribution of sample proportions leads or may tends to approximate a normal distribution and is an unbiased estimator that has a graph that is usually distributed and is not skewed. In other words, simply, we can also say that the population proportion is basically defined to be as the mean of the sample proportion. The population proportion is basically equaled the expected value of the sample proportion.

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Answer:

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Step-by-step explanation:

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