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Papessa [141]
1 year ago
6

Mrs. Ronilo had her students make a stem-and-leaf plot of the heights of all of the students in the class. The mean was 55. Dave

was absent the day they did this, and he is 57 inches tall. How does adding him into the data change the measures of central tendency?
Mathematics
2 answers:
shutvik [7]1 year ago
8 0
Given that the mean is 55 inches  and Dave is 57 inches, he would have increased the mean of the height in the stem-and-leaf plot that the students were making. This is however is also dependent upon the central tendency that was used, in this case the central tendency is mean or average. 
Nookie1986 [14]1 year ago
7 0

Answer:

mean is increased

Step-by-step explanation:

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An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
1 year ago
An aquarium has a base in the shape of a trapezoid. The base is 90 cm long at the front, 60 cm long at the back, and 30 cm wide
Nonamiya [84]

Answer:

Step-by-step explanation:

First calculate for the area of the trapezoid (the formula is (base + base / 2) x height):

60 cm + 90 cm = 150 cm

150 cm / 2 = 75 cm

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Now 1 cm² = 1 mL and 1000 mL = 1 L

2250 cm² = 2250 mL

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5 0
2 years ago
A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract
KengaRu [80]

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Step-by-step explanation:

Question 1)

Two lines, with their corresponding equations are given and we have to find the solution to the system of equations.

The given lines are:

Equation of Line 1:

y=\frac{-7}{4}x+\frac{5}{2}

This line passes through the points: (0, 2.5) , (2.2, -1.4)

Equation of Line 2:

y=\frac{3}{4}x-3

This line passes through the points (0, -3) , (2.2, -1.4)

By looking at the graph/given data we have to find the solution of these linear equations.

Remember that the solution of linear equations is an ordered pair, through which both the lines pass i.e. the point at which both the given lines intersect is the solution of the linear equations.

From the given data we can see that both the lines pass through one common point, (2.2, -1.4). Since, both lines pass through this point, this means this is the point of intersection of the lines and hence there solution.

So, the answer to this questions is (2.2, -1.4)

Question 2)

The given equations are:

y = 1.5x - 1                                        Equation 1

y = 1                                                  Equation 2

We can solve these equations by method of substitution.

Substituting the value of y from Equation 2, in Equation 1, we get:

1 = 1.5x - 1

1 + 1 = 1.5x

2 = 1.5x

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the given linear equations is (1.33, 1)

5 0
1 year ago
Read 2 more answers
Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi
timama [110]

Answer:

(a)The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Therefore, the length of the fence is  97\frac{1}{2}$ feet

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet

Similarly:

x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet

The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Length of the Fence

The fence is rectangular shaped with:

Length = 31\frac{1}{2}$ feet

Width = 17 \frac{1}{4}$ feet

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

=2(31\frac{1}{2}+17 \frac{1}{4})\\=2(31+17+\frac{1}{2}+ \frac{1}{4})\\=2(48+ \frac{3}{4})\\=96+\frac{3}{2}\\=97\frac{1}{2}$ feet

8 0
2 years ago
Sven is trying to find the maximum amount of time he can spend practicing the five scales of piano music he is supposed to be wo
Katena32 [7]

Answer:

He should spend 3 minutes or less on each scale

Sven made a mistake in the symbol of inequality, placing lesser or equal instead of greater or equal

Step-by-step explanation:

Let

t ------> is the number of minutes he spends on each scale

Remember that the phrase "at least"  is equal to "greater than or equal"

so

The inequality that represent this scenario is

70-5t \geq 55

solve for t

-5t \geq 55-70

-5t \geq -15

Multiply by -1 both sides

5t \leq 15

Divide by 5 both sides

t \leq 3

Sven is incorrect

He should spend 3 minutes or less on each scale

Sven made a mistake in the symbol of inequality, placing lesser or equal instead of greater or equal

5 0
1 year ago
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