3n - 3 + 2n + 4
(3n + 2n) + (-3 + 4)
5n + 1
1 journal = 280 grams
3 journals = 280 * 3
280 * 3 = 840
Total weight of 3 journals = 840 grams
| x - 8| = 3
x - 8 = 3 - (x - 8) = 3
x = 3 + 8 -x + 8 = 3
x = 11 -x = 3 - 8
-x = - 5
x = 5
Minimum : 5% Maximum : 11% if u need them added it is 16%
We will use the law of cosines
<span>side a² = b² + c² -2bc • cos(A)
</span><span>side a² = 729 + 196 -2*27*14 * cos (46)
</span><span>side a² = 925 -(756 * 0.69466)
</span>side a² = <span><span>399.83704
</span>
side a = </span><span><span><span>19.995925585
</span>
</span>
</span>
We could round that to 20
a = 20 b = 27 c =14
We can calculate a triangle's area when we know all 3 sides by using Heron's Formula
<span>area = square root (s • (s - a) • (s - b) • (s - c))
where s is the semi-perimeter </span>
semi-perimeter<span> = (side a + side b + side c) ÷ 2</span>
s = (20 + 27 + 14) / 2
s = 30.5
Now we use Heron's Formula
area = square root (s • (s - a) • (s - b) • (s - c))
area = square root (30.5 • (<span>30.5 - 20) • (</span><span>30.5 - 27) • (</span><span>30.5 - 14))</span>
area = square root (30.5 • (10.5) • (3.5) • (<span>16.5))</span>
<span>area = square root (18494.4375)
</span>
<span><span><span>area = 135.9942553934
</span>
</span>
</span>which rounds to
136 square feet
Source:
http://www.1728.org/triang.htm
Let 
....(1)
Multiply both sides of equation (1) by 10.
.... (2)
Multiply both sides of equation (1) by 100.
... (3)
Subtract equation (2) from equation (3)
Hence, the required fraction form is 
.... Answer.
