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lukranit [14]
2 years ago
8

Margo has 15 pounds of clay, Tim has 10 pounds of clay, Tray has 13 pounds of clay, Lila has 14 pounds of clay, and Jerry has 13

pounds of clay. How can they redistribute the clay so that they all have the same amount?
Check all that apply.

Margo should give away 2 pounds of clay.
Margo should be given 2 pounds of clay.
Tim should be given 1 pound of clay.
Lila should give away 1 pound of clay.
When fairly balanced everyone will have 14 pounds of clay.
When fairly balanced everyone will have 13 pounds of clay.
Mathematics
2 answers:
Natasha_Volkova [10]2 years ago
8 0
There are 65 pounds total if you add all pounds together. there are five student. 65/5 is 13 so if redistributed everyone will have 13. Margo should give away 2 pounds to Tim to give him twelve and Lila should also give one to Tim. So that he has 13 as well as everyone else.(If math and reason is needed to explain how answers where gotten) 

Your answers are:
Margo gives 2
Lila Gives 1 
Everyonoe will have 13
blsea [12.9K]2 years ago
6 0

Answer:

option 1, 4 and 6

Step-by-step explanation: cause i said so..

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weavers are making a carpet from a scale drawing. The carpet will be 10 ft by 14 ft. Every 5 in. on the drawing represents 7 ft
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Answer:

Wheres the drawing

Step-by-step explanation:

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Two random samples are taken from private and public universities
kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

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This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

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The answer is D
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What percent of 84 is 12?
lozanna [386]
So here is what we have

12 is what we need

out of the 84 we have

so...

12/84= .1428571429

and lets check our work

.1428571429 X 84 = 12

now lets convert it to a percent

.1428571429 X 100 = 14.28571429%

so the answer is 

14.28571429%
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