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1 year ago

Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number

Mathematics

2 answers:

Anastasy [175]1 year ago

6 0

Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

Lisa [10]1 year ago

6 0

Answer:

In order to reach from 170 to 410, we have to take 2 jumps of 100 and 4 jumps of 10.

Step-by-step explanation:

We have to count from 170 to 410.

We can only use tens and hundreds to do so.

First, we take a jump of 100.

170 + 100 = 270

We, again take a jump of 100.

270 + 100 = 370

We, again take a jump of 100.

370 + 100 = 470

But, we need to reach 410 which is way behind on the number line. Thus, after reaching 370 we cannot take a jump of 100.

Thus, 370 can be considered as a benchmark number.

After 370, we take jumps of 10 only.

370 + 10 = 380

380 + 10 = 390

390 + 10 = 400

400 + 10 = 410

Thus, we have reached the required number.

So, in order to reach from 170 to 410, we have to take 2 jumps of 100 and 4 jumps of 10.

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In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground

Nikitich [7]

Answer:

$n= 1500$ represent the random sample selected

$X= 1188$ represent the number of pots that were bare ground (no vegetation

$\hat p=\frac{X}{n}$

And replacing we got:

$\hat p=\frac{1188}{1500}= 0.792$

So then the sample proportion of bare ground spots is 0.792 for this sample

Step-by-step explanation:

We have the following info given from the problem:

$n= 1500$ represent the random sample selected

$X= 1188$ represent the number of pots that were bare ground (no vegetation)

And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

$\hat p=\frac{X}{n}$

And replacing we got:

$\hat p=\frac{1188}{1500}= 0.792$

So then the sample proportion of bare ground spots is 0.792 for this sample

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Joey wants to build a rectangular garden. He plans to use a side of a river for one side of the garden, he will not place fencin

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The standard form of the equation of a parabola is x = y2 + 10y + 22. What is the vertex form of the equation?

iVinArrow [24]

From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that 4p = 4, so p = 1. Then the focus is one unit above the vertex, at (0, 1), and the directrix is the horizontal line y = –1, one unit below the vertex.

vertex: (0, 0); focus: (0, 1); axis of symmetry: x = 0; directrix: y = –1

Graph y2 + 10y + x + 25 = 0, and state the vertex, focus, axis of symmetry, and directrix.

Since the y is squared in this equation, rather than the x, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking y-values first and then finding the corresponding x-values for x = –y2 – 10y – 25:

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This tells me that 4p = –1, so p = –1/4. Since the parabola opens to the left, then the focus is 1/4 units to the left of the vertex. I can see from the equation above that the vertex is at (h, k) = (0, –5), so then the focus must be at (–1/4, –5). The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is 1/4 units to the right of the vertex. Putting this all together, I get:

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The y part is squared, so this is a sideways parabola. I'll get the y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.

y2 + 6y – 15 = –12x
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1 year ago