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mash [69]
1 year ago
14

Russell collected 30 stones at his grand parents' house. He decided to give his little sister 1 / 5 of the stones. How many ston

es did he give his sister?
Mathematics
1 answer:
STALIN [3.7K]1 year ago
5 0
He gives his sister 6 stones

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Write a word problem that can be solved by ordering three decimals to thousandths. Include a solution
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Then make up a word problem that you can use decimals in.
6 0
1 year ago
4 markers cost $7.04. Which equation would help determine the cost of 7 markers??
aleksley [76]

Answer: 12.32

Step-by-step explanation:

7.04 divided by 4 = 1.76. 1.76 x 7 = 12.32.

7 0
1 year ago
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Caswell started studying how the number of branches on his tree grows over time. The relationship between the elapsed time ttt,
ipn [44]

Answer:

t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.

Step-by-step explanation:

100 = 5 * 10^(0.3t), solve for t

Divide both sides by 5:

20 =10^(0.3t)

Take the log of both sides:

0.3t =log(20)

Divide both sides by 0.3:

Multiply the RHS by 10 / 10

t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.

8 0
1 year ago
Read 2 more answers
The sum of an infinite geometric sequence is seven times the value of its first term.
Radda [10]

Answer:

a). r = \frac{6}{7}

b). At least 5 terms should be added.

Step-by-step explanation:

Formula representing sum of infinite geometric sequence is,

S_{\inf}=\frac{a}{1-r}

Where a = first term of the sequence

r = common ratio

a). If the sum is seven times the value of its first term.

    7a=\frac{a}{1-r}

    7=\frac{1}{1-r}

    7(1 - r) = 1

    7 - 7r = 1

    7r = 7 - 1

    7r = 6

    r = \frac{6}{7}

b). Since sum of n terms of the geometric sequence is given by,

    S_{n}=\frac{a(1-r^{n})}{1-r}

If the sum of n terms of this sequence is more than half the value of the infinite sum.

\frac{a[1-(\frac{6}{7})^{n}]}{1-\frac{6}{7}} >  \frac{7a}{2}

\frac{1-(\frac{6}{7})^{n}}{1-\frac{6}{7}}> \frac{7}{2}

\frac{1-(\frac{6}{7})^{n}}{\frac{1}{7}}> \frac{7}{2}

1-(\frac{6}{7})^{n}> \frac{7}{2}\times \frac{1}{7}

1-(\frac{6}{7})^{n}> \frac{1}{2}

-(\frac{6}{7})^{n}> -\frac{1}{2}

(\frac{6}{7})^{n}< \frac{1}{2}

(0.85714)^{n}<  (0.5)

n[log(0.85714)] < log(0.5)

-n(0.06695) < -0.30102

n > \frac{0.30102}{0.06695}

n > 4.496

n > 4.5

Therefore, at least 5 terms of the sequence should be added.

8 0
2 years ago
If  BD BC, BD = 5x – 26, BC = 2x + 1, and AC = 43, find AB.
Bumek [7]

Answer:

AB = 24

Step-by-step explanation:

BD = 5x – 26

BC = 2x + 1

AC = 43

Using the segment addition postulate, AC = AB + BC.

We know that BD = BC, BD = 5x-26 and BC = 2x+1.  We can set up an equation to find the value of x:

5x - 26 = 2x + 1   Subtract 2x from each side

5x - 26 - 2x = 2x + 1 - 2x

3x-26 = 1  Add 26 to each side

3x-26+26 = 1+26

3x=27  Divide both sides by 3

3x/3 = 27/3

x = 9

This means that BC = 2x + 1 = 2(9) + 1 = 18 + 1 = 19.

We know that AC = AB + BC; using our given information as well as the value of BC we just found, we have

43 = AB + 19  Subtract 19 from each side

43 - 19 = AB + 19 - 19

24 = AB

4 0
1 year ago
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