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Slav-nsk [51]
1 year ago
10

At a local baseball game there are 3 hot dog vendors. collectively the vendors sold 1,700 hot dogs. if vendor a sold 456, vendor

b sold 607, and vendor c sold 637, what percentage of the total did each vendor sell? (round to the nearest percent.) a) 26 percent, 40 percent, 44 percent b) 45 percent, 37 percent, 18 percent c) 27 percent, 36 percent, 37 percent d) 30 percent, 35 percent, 35 percent
Mathematics
2 answers:
Vera_Pavlovna [14]1 year ago
8 0
The answer is C.

Vendor A= 456/1700, which is .268 or 27%
Vendor B= 607/1700, which is .357 or 36%
Vendor C= 637/1700, which is .374 or 37%

For a total of 100%
pav-90 [236]1 year ago
5 0
The correct answer is c) 27%, 36%, AND 37% divide how many hot dogs the vendor sold by 1700 and then round to find the percentage
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Searches related to Elon sat on the dock with his fishing rod, when suddenly he felt the rod being pulled down! He reeled in his
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The graph is attached.

We first graph the point where his catch reached the surface, (35, 0).  Since it travels upward at a constant rate, the graph will be linear.  We also need to know where it starts (what depth it is at when he begins reeling it in).  We can use the formula d=rt as a template for our function.  d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.

To find how far the catch had to travel to reach the surface, we set up our equation as:
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From the probability distribution table, the probability of having 4 siblings at the game is 0. This is the lowest out of all the given value in the probability distribution table. Therefore, it is the least likely event.

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Answer:

"<em>The probability that the amount of time spent on leisure activities per day for a randomly selected adult from the population of interest is less than 6 hours per day</em>" is about 0.8749.

Step-by-step explanation:

We have here a <em>random variable</em> that is <em>normally distributed</em>, namely, <em>the</em> <em>time spent on leisure activities by adults living in a household with no young children</em>.

The normal distribution is determined by <em>two parameters</em>: <em>the population mean,</em> \\ \mu, and <em>the population standard deviation,</em> \\ \sigma. In this case, the variable follows a normal distribution with parameters \\ \mu = 4.5 hours per day and \\ \sigma = 1.3 hours per day.

We can solve this question following the next strategy:

  1. Use the <em>cumulative</em> <em>standard normal distribution</em> to find the probability.
  2. Find the <em>z-score</em> for the <em>raw score</em> given in the question, that is, <em>x</em> = 6 hours per day.
  3. With the <em>z-score </em>at hand, we can find this probability using a table with the values for the <em>cumulative standard normal distribution</em>. This table is called the <em>standard normal table</em>, and it is available on the Internet or in any Statistics books. Of course, we can also find these probabilities using statistics software or spreadsheets.

We use the <em>standard normal distribution </em>because we can "transform" any raw score into <em>standardized values</em>, which represent distances from the population mean in standard deviations units, where a <em>positive value</em> indicates that the value is <em>above</em> the mean and a <em>negative value</em> that the value is <em>below</em> it. A <em>standard normal distribution</em> has \\ \mu = 0 and \\ \sigma = 1.

The formula for the <em>z-scores</em> is as follows

\\ z = \frac{x - \mu}{\sigma} [1]

Solving the question

Using all the previous information and using formula [1], we have

<em>x</em> = 6 hours per day (the raw score).

\\ \mu = 4.5 hours per day.

\\ \sigma = 1.3 hours per day.

Then (without using units)

\\ z = \frac{x - \mu}{\sigma}

\\ z = \frac{6 - 4.5}{1.3}

\\ z = \frac{1.5}{1.3}

\\ z = 1.15384 \approx 1.15

We round the value of <em>z</em> to two decimals since most standard normal tables only have two decimals for z.

We can observe that z = 1.15, and it tells us that the value is 1.15 standard deviations units above the mean.

With this value for <em>z</em>, we can consult the <em>cumulative standard normal table</em>, and for this z = 1.15, we have a cumulative probability of 0.8749. That is, this table gives us P(z<1.15).  

We can describe the procedure of finding this probability in the next way: At the left of the table, we have z = 1.1; we can follow the first line on the table until we find 0.05. With these two values, we can determine the probability obtained above, P(z<1.15) = 0.8749.

Notice that the probability for the z-score, P(z<1.15), of the raw score, P(x<6) are practically the same,  \\ P(z. For an exact probability, we have to use a z-score = 1.15384 (without rounding), that is, \\ P(z. However, the probability is approximated since we have to round z = 1.15384 to z = 1.15 because of the use of the table.

Therefore, "<em>the probability that the amount of time spent on leisure activities per day for a randomly selected adult from the population of interest is less than 6 hours per day</em>" is about 0.8749.

We can see this result in the graphs below. First, for P(x<6) in \\ N(4.5, 1.3) (red area), and second, using the standard normal distribution (\\ N(0, 1)), for P(z<1.15), which corresponds with the blue shaded area.

5 0
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The top of a ladder is 4m up a vertical wall.The bottom is 2m from the wall.The coordinate axes are the wall and the horizontal
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Answer:

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Step-by-step explanation:

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Part b) A square box just fits under the ladder.Find the coordinates of the point where the box touches the ladder.

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y=x=\frac{4}{3}

therefore

The coordinates of the point are (\frac{4}{3},\frac{4}{3})

6 0
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