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2 years ago

10

At a local baseball game there are 3 hot dog vendors. collectively the vendors sold 1,700 hot dogs. if vendor a sold 456, vendor

b sold 607, and vendor c sold 637, what percentage of the total did each vendor sell? (round to the nearest percent.) a) 26 percent, 40 percent, 44 percent b) 45 percent, 37 percent, 18 percent c) 27 percent, 36 percent, 37 percent d) 30 percent, 35 percent, 35 percent

2 answers:

Vera_Pavlovna [14]2 years ago

8 0

The answer is C.

Vendor A= 456/1700, which is .268 or 27%
Vendor B= 607/1700, which is .357 or 36%
Vendor C= 637/1700, which is .374 or 37%

For a total of 100%

pav-90 [236]2 years ago

5 0

The correct answer is c) 27%, 36%, AND 37% divide how many hot dogs the vendor sold by 1700 and then round to find the percentage

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Answer: Barbarino's rentals has a better deal.

She has to drive 887.5 miles to spend the same amount at either company.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

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<em>$99 PER WEEK </em>
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<em>Barbarino's rentals (B) </em>

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For "A"

Cost = 0.11 (432-100) + 99 = $135.52

For "B"

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The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

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The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

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4

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

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There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

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The first sample size is $n_1 = 51$

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The second sample size is $n_2 = 41$

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The second standard deviation is $\sigma _2 = 12.8 \ g$

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=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

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Answer:

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