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expeople1 [14]
1 year ago
10

If an intravenous solution containing 123 mg of a drug substance in each 250-mL bottle is to be administered at the rate of 200

μg of drug per minute, how many milliliters of the solution would be given per hour?
Mathematics
1 answer:
12345 [234]1 year ago
7 0

Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

1000x = 200

x = \frac{200}{1000}

x = 0.2mg

In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?

1 minute - 0.2 mg

60 minutes - x mg

x = 60*0.2

x = 12mg

In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.

123mg - 250mL

12 mg - xmL

123x = 250*12

x = \frac{250*12}{123}

x = 24.39mL

24.39mL of the solution would be given per hour.

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Answer:

$(55-3m) is the amount of money she has left

Step-by-step explanation:

In this question, we are asked to give an expression to represent how much money was left after Sarah had bought some certain stuffs at some prices using the money she received at her birthday.

Firstly, we identify that the total amount of money she has to spend is $55.

Now let’s project her total spendings. She bought 3 shirts with each shirt costing $m.

The total amount spent on the shirts is thus; 3 * $m = $3m

The amount of money she has left is the difference.

Mathematically, this is equal to $55 - $3m

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Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number
Anastasy [175]
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

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Julie is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour. When th
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2 years ago
Triangle N T M is shown. Angle N T M is a right angle. An altitude is drawn from point T to point U on side N M to form a right
stich3 [128]

Answer:

The value of y is 6\sqrt{3} units ⇒ 2nd answer

Step-by-step explanation:

In the attached figure

∵ ∠MTN is a right angle

∵ TU is the altitude of the triangle

- There are some rules in this triangle let us revise them

  • (NT)² = NU . NM
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∵ NU = 9 units

∵ UM = 3 units

∵ MN = UM + NU

∴ MN = 3 + 9 = 12 units

- By using the 1st rule above

∴ (NT)² = 9 × 12

∴ (NT)² = 108

- Take a square root to both sides

∴ NT = \sqrt{108}

- Simplify the root

∴ NT = 6\sqrt{3} units

∵ NT is y

∴ y = 6\sqrt{3} units

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Which graph shows the solution to the inequality Negative 3 x minus 7 less-than 20
Aleksandr-060686 [28]

Answer:

A number line goes from negative 10 to positive 10. An open circle appears at negative 9. The number line is shaded from negative 9 through positive 10.

Step-by-step explanation:

we have

-3x-7

Solve for x

Adds 7 both sides

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Divide by -3 both sides

Remember that

When you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

x> 27/(-3)\\x>-9

The solution is the interval (-9,∞)

therefore

A number line goes from negative 10 to positive 10. An open circle appears at negative 9. The number line is shaded from negative 9 through positive 10.

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