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2 years ago

There are 30 businesses with 4 executives each for the new office building. Each business needs one office for each of its

Mathematics

1 answer:

Zanzabum2 years ago

8 0

Answer:

Step-by-step explanation:

B is the right one because the question says that every 4 executives can go into 1 office

You might be interested in

Which number in the monomial 215x18y3z21 needs to be changed to make it a perfect cube?

Murljashka [212]

Remember
xyz=(x)(y)(z)
if x and y and z are all perfect cubes, xyz is also a perfect cube

remmeber
(x^n)^m=x^(mn)
so if it is perfect cube it can be factored into
(x^n)^3, such taht n is a whole number
basiclaly, see if the expoent is divisble by 3

all of them should be perfect cubes

215x^18y^3z^21

split them up to see which ones need changing

215=5*43, not a perfect cube
could be changed to 6^3, which is 216

x^18=(x^6)^3

y^3=y^3
z^21=(z^7)^3

the 215 needs to be changed

8 0

2 years ago

Read 2 more answers

A normal distribution curve, where x = 70 and σ = 15, was created by a teacher using her students’ grades. What information abou

mash [69]

Answer:

The median and mode of the students grade is 70.

Most of the students scored between 40 and 100.

Step-by-step explanation:

From the provided information it can be seen that the mean of the distribution is, <em>μ</em> = 70 and the standard deviation is, <em>σ</em> = 15.

For a Normal distributed data the mean, median and mode are the same.

So, the median and mode of the students grade is 70.

The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

$P(\mu-\sigma$

$P(\mu-2\sigma$

$P(\mu-3\sigma$

Assuming that maximum marks of the exam is 100, it can be said that most of the students scored between 40 and 100.

3 0

2 years ago

Read 2 more answers

Evaluate 8a-1+0.5b8a−1+0.5b8, a, minus, 1, plus, 0, point, 5, b when a=\dfrac14a=

professor190 [17]

Answer: $6$

Step-by-step explanation:

Given the following expression:

$8a-1+0.5b$

You need to substitute the given values of "a" and "b" into the expression. Notice that these values are:

$a=\frac{1}{4}\\\\b=10$

Then;

$8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)$

Now you must solve the multiplications:

$=\frac{8}{4}-1+5=2-1+5$

The final step is to add the numbers. Therefore, you get the following answer:

$=6$

7 0

2 years ago

Read 2 more answers

The flathead rail tunnel in Montana is about 7 3/4 miles long. A train travels at a speed of 3/4 mile per mile minute.how long w

kogti [31]

7 3/4 × 3/4 = So u add 3×3=9
Then add 4×4=16 Give you 9/16
Then you add that 7 you left out with 9/16
But just the 9 not the 16
7 × 9 = 63 And your answer is 63/16
Hope i help :-)

5 0

2 years ago

Read 2 more answers

Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not

tangare [24]

Answer:

$\bar p_1=0.05\\\bar p_2=0.067$

b-Check illustration below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let $p_1 \& p_2$ denote processes 1 & 2.

For $p_1$ : T1=10,n1=200

For $p_2$ :T2=20,n2=300

Therefore

$\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067$

b. To test for hypothesis:-

$H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05$

ii.For a two sample Proportion test

$Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\$

iii. for $\frac{\alpha}{2}=(-1.96,+1.96)$ (0.5 alpha IS 0.025),

reject $H_o$ if $|Z|>1.96$

iv. Do not reject $H_o$ . The noncomforting proportions are not significantly different as calculated below:

$z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}$

z=-0.78

c. $(1-\alpha).100\%$ for the p1-p2 is given as:

$(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645 \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\$

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0

2 years ago