Answer:
Step-by-step explanation:
given that an electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each
Sample space for selecting one resistor from first box
= {9, 10, 11, 12, 13}
A = {11,12,13} (because >10)
Sample space for selecting one resistor from second box
={18,19,20,21,22}
B={18}
Sample space for sum would be
{27, 28, 29, 30, 31, 32, 33, 34, 35}
C = {(9,19) , (10,18)}
