Answer:
(D)y ≤ 3x − 1 y ≥ −x + 4
Step-by-step explanation:
The line f(x) is solid and goes through the points (0, 4) and (4, 0) and is shaded above the line.
The line that satisfies the point (0,4) and (4,0) is y=-x+4
Since it is shaded above the line, we have the inequality sign ≥.
Therefore, one of the lines is y≥-x+4
In the equation of the line y=3x-1
When x=0, y=3(0)-1=-1
When x=2, y=3(2)-1=5
Since it is shaded below the line, we have the inequality sign ≤ .
Therefore, the other line is y≤3x-1.
The correct option is D.
Answer:
Volume of the hive is 4712.4 square inches.
Step-by-step explanation:
Since hive has the shape of a cone with radius = 15 inches and height = 20 inches
Therefore, volume of the given cone =
Area of the circular base = πr²
Area = π(15)²
= 225π
Volume of the cone =
= 1500π
= 4712.39
≈ 4712.4 square inches
Therefore, volume of the hive is 4712.4 square inches.
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is . Thus, there are only 35 ways to distribute the blackboards in this case.