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Margarita [4]
2 years ago
7

The grades in period 3 Algebra 2 have an average of 82% and vary by 12 percentage points. Formulate an absolute value equation t

hat could be used to solve for the maximum and minimum grade.
|x______ | = _______

x = __________ (smaller number here)

x = _______ (larger nember here)

Blank 1:
Blank 2:
Blank 3:
Blank 4:
Mathematics
1 answer:
Sati [7]2 years ago
4 0

Answer:

|x - 85| =  12

x =  73 \  (smaller\  number )

x =  97 \  (larger \ number )

Step-by-step explanation:

From the question we are told that

  The  grade is  k  =  85\%

   The  variation is  v =  12 \%

Generally the absolute value equation is mathematically represented as

        |x - 85| =  12

=>  x -85 =  \pm 12

So

    x =  85 + 12

    x =  97 \  (larger \ number )

And

     x =  -12 + 85

=>  x =  73 \  (smaller\  number )

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julsineya [31]

Answer: There are 3 strips that can be cut from the roll of ribbon.

Step-by-step explanation:

since we have given that

Length of a ribbon is given by

7\frac{1}{2}\ ft\\\\=\frac{15}{2}\ ft

Length of pieces of ribbon cut into strips is given by

2\frac{1}{2}\ ft\\\\=\frac{5}{2}\ ft

So, we need to find the number of strips that can be cut is given by

\text{ Number of strips }=\frac{\text{Length of roll}}{\text{ Length of strip}}\\\\=\frac{\frac{15}{2}}{\frac{5}{2}}\\\\=\frac{15\times 2}{2\times 5}\\\\=\frac{15}{5}\\\\=3

Hence, there are 3 strips that can be cut from the roll of ribbon.

6 0
2 years ago
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3.18x16 =_____hundredths +_____hundredths=_____hundredths=____
kari74 [83]
3.18x16=50.88 hundredths
4 0
1 year ago
2. In the product of (4a3 + 5a2 – 11a) and (-15 + 3a – 7a2), the co-efficient of a4 is …………………… .
vekshin1

Answer:

- 23

Step-by-step explanation:

We could do this the long way and expand the whole product or note that the a^{4} terms arise from the product of the a³ and a terms and the product of the a² and a² terms, that is

4a³ × 3a = 12a^{4}

+ 5a² × - 7a² = - 35a^{4}

Summing gives

12a^{4} - 35a^{4} = - 23a^{4}

with coefficient - 23

5 0
2 years ago
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"The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of my two numbers is 45" (b) Write down
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Answer:

Step-by-step explanation:

15 and 3

6 0
2 years ago
Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many
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Answer:

a) 20 ways

b) 10 ways

Step-by-step explanation:

When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.

Part a)

We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2

General formula of permutations of n objects taken r at time is:

nPr=\frac{n!}{(n-r)!}

Using the value of n=5 and r=2, we get:

5P2=\frac{5!}{(5-2)!} =20

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.

Part b)

Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.

The general formula of combinations of n objects taken r at a time is:

nCr=\frac{n!}{r!(n-r)!}

Using the value of n=5 and r=2, we get:

5C2=\frac{5!}{2!(5-2)!} =10

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.

3 0
2 years ago
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