Divide 3/4 by 2 and then square it. 3/4/2=3/8 squared which is 9/64.
Answer:
Missing same value is 0.02
Step-by-step explanation:
Instead of multiplying big decimal numbers we put short cut by making 0.98 as a difference of near integer and one decimal.
i.e 0.98 =1-0.02
Since 0.02 is the same for other also other term
0.73 = 0.75-0.02
Now product can be done very easily.
Steps are shown below:
0.98x0.73
= (1-0.02) (0.75-0.02)
= 0.75 -0.02(1+0.75)+0.0004
= 0.7504-(0.035)
= 0.7154
=0.44
Answer: P(hist& french)=16/200=0.08
Step-by-step explanation:
To find the required probability we have to know what is the number of students that take both History and French ( Intersection of 2 circles in Venn diagram)
1. Lets find the number of students that take History or French or both.
We know that 8% from 200 take neither History or French. So number or students who take History or French or both is 200-200*0.08=184
2. Let number of students that takes French (or both Fr+Hist)=x (left circle)
So number of students that takes History (or both Fr+Hist)=4x (right circle)
So number of students that take both French+History= 10% from 4x or
0.1*4x=0.4x (circles' intersection)
3. Now we have the equation as follows:
x+4*x-0.4*x = 184
4.6*x=184
x=40 students takes French (or both French+ History)
4*x= 40*4=160 students takes History (or both French+ History)
10% from 160 =0.1*160=16 students takes both History and French
P(hist& french)=16/200=0.08
System 1: The solution is (x, y) = (-4, 5)
System 2: The solution is 
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 7 ------ eqn 1
-3x - 5y = -13 --------- eqn 2
We can solve by elimination method
Multiply eqn 1 by 3
6x + 9y = 21 ------ eqn 3
Multiply eqn 2 by 2
-6x - 10y = -26 ------- eqn 4
Add eqn 3 and eqn 4
6x + 9y -6x - 10y = 21 - 26
-y = -5
y = 5
Substitute y = 5 in eqn 1
2x + 3(5) = 7
2x + 15 = 7
2x = -8
x = -4
Thus the solution is (x, y) = (-4, 5)
<h3><em><u>
Second system of equation is:</u></em></h3>
8 - y = 3x ------ eqn 1
2y + 3x = 5 ----- eqn 2
We can solve by susbtitution method
From given,
y = 8 - 3x ----- eqn 3
Substitute eqn 3 in eqn 2
2(8 - 3x) + 3x = 5
16 - 6x + 3x = 5
3x = 16 - 5
3x = 11
Substitute the above value of x in eqn 3
y = 8 - 3x
Thus the solution is
Answer:
4y is your answer........
