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PtichkaEL [24]
1 year ago
15

The perimeter of a rectangle is represented by 4x2 + 5x − 2. The perimeter of a smaller rectangle is represented by x2 + 3x + 5.

Which polynomial expression BEST represents how much larger the first rectangle is than the smaller rectangle?
Mathematics
2 answers:
REY [17]1 year ago
6 0
<span>4x2 +5x - 2 -x2 +3x +5 Simplified: 3x2 + 8x +3 In order to determine the difference in size, you must subtract the perimeter of the smaller rectangle from the perimeter of the larger rectangle.</span>
pantera1 [17]1 year ago
5 0

Answer:

3x^{2} +2x-7                                                                                                                                        

Step-by-step explanation:

Given :

Perimeter of a bigger rectangle is represented by 4x^{2} +5x-2

Perimeter of a smaller  rectangle is represented by x^{2} +3x+5

To Find : Polynomial expression that represents how much larger the first rectangle is than the smaller rectangle.

Solution :

Subtract the equation of perimeter of  smaller rectangle from equation of  perimeter of a bigger rectangle :

⇒  4x^{2} +5x-2 - (x^{2} +3x+5)

⇒4x^{2} +5x-2-x^{2} -3x-5

⇒3x^{2} +2x-7

So, Polynomial expression that represents how much larger the first rectangle is than the smaller rectangle is 3x^{2} +2x-7.

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What is 4 square root of 81 to the fifth power in exponential form
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Answer:

B is the answer.

Step-by-step explanation:

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Two standard dice are rolled and their face values multiplied. What is the probability that the product is prime or ends in 0?
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2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
1 year ago
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