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PtichkaEL [24]
1 year ago
15

The perimeter of a rectangle is represented by 4x2 + 5x − 2. The perimeter of a smaller rectangle is represented by x2 + 3x + 5.

Which polynomial expression BEST represents how much larger the first rectangle is than the smaller rectangle?
Mathematics
2 answers:
REY [17]1 year ago
6 0
<span>4x2 +5x - 2 -x2 +3x +5 Simplified: 3x2 + 8x +3 In order to determine the difference in size, you must subtract the perimeter of the smaller rectangle from the perimeter of the larger rectangle.</span>
pantera1 [17]1 year ago
5 0

Answer:

3x^{2} +2x-7                                                                                                                                        

Step-by-step explanation:

Given :

Perimeter of a bigger rectangle is represented by 4x^{2} +5x-2

Perimeter of a smaller  rectangle is represented by x^{2} +3x+5

To Find : Polynomial expression that represents how much larger the first rectangle is than the smaller rectangle.

Solution :

Subtract the equation of perimeter of  smaller rectangle from equation of  perimeter of a bigger rectangle :

⇒  4x^{2} +5x-2 - (x^{2} +3x+5)

⇒4x^{2} +5x-2-x^{2} -3x-5

⇒3x^{2} +2x-7

So, Polynomial expression that represents how much larger the first rectangle is than the smaller rectangle is 3x^{2} +2x-7.

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You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
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Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

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Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

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Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

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c) For what value of the independent variable will the value of the function be equal to 0.

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