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wel
2 years ago
11

Assume that you pay $2,849.84 in state property taxes every year. If your property has an assessed value of $41,302, what is you

r state’s property tax rate? a. 0.077 b. 0.032 c. 0.014 d. 0.069
Mathematics
2 answers:
Olenka [21]2 years ago
4 0
The answer would be D
Katena32 [7]2 years ago
3 0

Answer:

Therefore, The correct option is D. 0.069

Step-by-step explanation:

Amount of the money paid in the state property taxes every year = $2849.84

The property owned has an assessed value.

Now, the assessed value of the property is $41302

We need to find the state's property tax rate.

\text{So, State's property tax rate = }\frac{\text{state's property tax}}{\text{assessed value}}\\\\\text{State's property tax rate = }\frac{2849.84}{41302}\approx 0.069

Therefore, The correct option is D. 0.069

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Kamila [148]
<span>The side b is opposite to the angle B, applying the law of the sines, we have:

</span>\frac{a}{sinA} = \frac{b}{sinB}
\frac{20}{sin30^0} = \frac{b}{sin45^0}
\frac{20}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{2} }{2} }
20* \frac{ \sqrt{2} }{2}  = b* \frac{1}{2}
\frac{20 \sqrt{2} }{2} = \frac{b}{2}
2*b =2*20 \sqrt{2}
2b = 40 \sqrt{2}
b =  \frac{40 \sqrt{2} }{2}
\boxed{b = 20 \sqrt{2} }
6 0
1 year ago
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The function A(b) relates the area of a trapezoid with a given height of 10 and
Natali5045456 [20]

The function of the trapezoid area is:

A(x)=(B+b)*h/2

Where B and b are the bases and h is the height.

With the given data: h=10 B and b =7 and x (it may vary which one is bigger)

-----------

So that function becomes:

A(x)=(7+x)*10/2

A(x)=(7+x)*5

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So if you want the inverse function, you have to operate to find x:

A(x)/5=7+x

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2 years ago
Write an arithmetic series for which S5 = 10.
Ludmilka [50]
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2 years ago
Perform the following computations. retail price of steel-belted radial tire = $89.50 discount offered = 10% federal tax = 12% l
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For the answer to the question above
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I hope my answer helped you. Feel free to ask more questions. Have a nice day!
4 0
2 years ago
Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0
2 years ago
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