Answer:
-2+sqrt(3)
Step-by-step explanation:
When cos(angle)=sqrt(3)/2
then sin(of that angle)= + or - 1/2 depending on the quadrant
Anyways 330 degrees is in the 4 quadrant. Cosine is positive there while sine is negative.
so sin(330)=-1/2
Formula for tan(x/2)=(1-cos(x))/sin(x)
Therefore tan(165)=tan(330/2)=(1-cos(330))/sin(330)=(1-sqrt(3)/2)/(-1/2)
Multiply top and bottom by 2 to get
tan(165)=(2-sqrt(3))/-1
tan(165)=-2+sqrt(3)
Sorry
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<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>

.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>

.
X-intercept has coordinates (x,0)
Y-intercept has coordinates (0,y)
So, the statement "<span> The ordered pair of x-intercept has a zero for the x-value" is false.
</span><span> The ordered pair of x-intercept has a zero for the y-value.</span>