Answer:
The true statement is: The probability that a randomly selected player on Team C is 10 years old is
.
Step-by-step explanation:
According to the table the total number of 10 years old players on Team C is 5 and the total number of all ages players (8, 9 and 10 years old) on Team C is 16, so the probability that a randomly selected player on Team C is 10 years old is 5/16.
The average weight in ounce for each piece of chocolate is 0.03.
Step-by-step explanation:
The heart-shaped box containing the chocolates has the weight of 2 pounds
The box contains 68 pieces of chocolates.To find the weight of each piece of chocolate, you divide the weight of the box with the number of chocolate pieces in the box.
This will be 2/68 = 0.0294117647
To the nearest hundredth you check the thousandths value and round off
In this case; 0.0294117647 = 0.03 pounds
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Keyword : pound, average, hundredth
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Answer:
The equation are:
1) h + s = 20
2) 4h = 1s
Step-by-step explanation:
Number of hats Elliott made = h
Number of scarfs Elliott made = s
total number of items Elliott made = 20
h + s = 20 ..[1]
1 hat uses 0.2 kilograms of yarn
1 hat = 0.2 kg of yarn
Then h hats will use = 0.2h kg of yarn
1 scarf uses 0.1 kilograms of yarn
1 scarf= 0.1 kg of yarn
Then s scarfs will use = 0.1s kg of yarn
She wants to twice as much as yarn for scarves for hats:
2 × (0.2h kg of yarn) = 0.1s kg of yarn
0.4h = 0.1s
4h = 1s...[2]
The equation are:
1) h + s = 20
2) 4h = 1s
Answer:
The company's chocolate bars weigh 1.6 ounces on average.
Step-by-step explanation:
We are given that a company claims that its chocolate bars weigh 1.6 ounces on average.
It took many large samples, and each time the mean weight of the sample was within the 95% confidence interval.
95% confidence level means a range of values that you can be 95% certain contains the true mean of the population.
Thus by definition we can say that The company's chocolate bars weigh 1.6 ounces on average.
Hence Option B is correct.
Answer:
Produce only Product B.
Step-by-step explanation:
The contribution margin per machine hour for product A is ...
($16 -$6)/(5 hour) = $2 per hour
The contribution margin per machine hour for product B is ...
($12 -$5)/(3 hour) ≈ $2.33 per hour
The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.