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FrozenT [24]
2 years ago
12

The present age of nitin is two times the present age of his sister pooja. After 7 years their ages will add to 68 years. Find t

heir ages
Mathematics
1 answer:
svlad2 [7]2 years ago
7 0
N=2p

(n+7) + (p+7) = 68

2p + 7 + p + 7 = 68

3p + 14 = 68

3p = 68 - 14 = 54

p=54/3=18

n=2p=36

Check: (18+7)+(36+7)=25+43=68  good



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Using the information given, select the statement that can deduce the line segments to be parallel. If there are none, then sele
Shtirlitz [24]

Answer:

AB = DC  

Step-by-step explanation:

Applying the information provide in the attached diagram , The statement that can deduce the line segments to be parallel is : AB = DC

when M2 = M3

attached below is the missing diagram as related to this question above

4 0
2 years ago
Suppose a snow cone has a paper cone that is 8 centimeters deep and has a diameter of 5 centimeters. The flavored ice comes in a
Neko [114]

check the picture below.


so the cone itself has a height of 8, and a radius of 2.5, and the spherical scoop, ready to melt in it, has a radius of 2.5.


namely, will the volume of the sphere be larger than the cone? in which case the melted ice-cream will overflow.


\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=2.5\\ h=8 \end{cases}\implies V=\cfrac{\pi (2.5)^2(8)}{3}\implies \implies \boxed{V=\cfrac{50\pi }{3}} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad r=2.5\implies V=\cfrac{4(\pi )(2.5)^3}{3}\implies \boxed{V=\cfrac{125\pi }{6}} \\\\\\ \textit{the sphere's volume is larger, so yes, it will overflow}

8 0
2 years ago
Read 2 more answers
A pile of coins, consisting of quarters and half dollars, it worth $11.75. If there are 2 more quarters than half dollars, how m
lord [1]
Let the number of half dollars be x,

number of quarters = x + 2
amount of half dollars = 0.5x
amount of quarters = 0.25(x + 2)
= 0.25x + 0.5
total amount = 0.5x + 0.25x + 0.5
= 0.75x + 0.5
0.75x + 0.5 = 11.75
0.75x = 11.25
x = 15
number of quarters = x + 2
= 15 + 2
= 17

There are 17 quarters and 15 half dollars.
3 0
2 years ago
Each of four students hands in a homework paper. Later the teacher hands back the graded papers randomly, one to each of the stu
Stella [2.4K]

Answer:

9 possible ways.

Step-by-step explanation:

To explain this problem i'm going to use letters and numbers (only as example). The letters correspond to a student and the numbers to a homework. Te correct form we have is:

<u>Student</u> ⇒ <u>Homework</u>

    A       ⇒    1

    B       ⇒    2

    C       ⇒    3

    D       ⇒    4

In how many ways can the papers be handed back such that every student receives someone else's paper?. To answer this we need to form every group of Student/Homework possible, but not taking into count the correct way (showing above)

Possible groups:

1) A-2/B-1/C-4/D-3

2)A-2/B-4/C-1/D-3

3)A-2/B-3/C-4/D-1

4)A-3/B-1/C-4/D-2

5)A-3/B-4/C-2/D-1

6)A-3/B-4/C-1/D-2

7)A-4/B-1/C-2/D-3

8)A-4/B-3/C-2/D-1

9)A-4/B-3/C-1/D-2

We have 9 possible ways,

3 0
2 years ago
What is the value of x, if 105% of 90 is equal to 200% of x?
lisov135 [29]

From the given equation

105% * 90 = 200% * x

105/100 * 90 = 200/100 * x

105*90 = 200*x

x = 105*90/200

X = 21*9/4

X = 189/4

x = 47.25

Value of x = 47.25 or 47 1/4

7 0
2 years ago
Read 2 more answers
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