So 72 pencils and 24 calculators
so greates number of identical calculators
this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule
to find the GCM, you factor 72 and group the like ones
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
so the common group is 2 times 2 times 2 times 3 or 24
so the greates number of packs is 24
so pencils
72 divided by 24=72/24=3
3 pencils per pack
24 divided by 24=24/24=1
1 calulator per pack
answer is 3 pencils and 1 calculator per pack
<u><em>Answer:</em></u>
A. (3x²-4x-5)(2x⁶-5)
<u><em>Explanation:</em></u>
<u>The fundamental theorem of Algebra states that:</u>
"A polynomial of degree 'n' will have exactly 'n' number of roots"
We know that the degree of the polynomial is given by the highest power of the polynomial.
Applying the above theorem on the given question, we can deduce that the polynomial that has exactly 8 roots is the polynomial of the 8th degree
<u>Now, let's check the choices:</u>
<u>A. (3x²-4x-5)(2x⁶-5)</u>
The term with the highest power will be (3x²)(2x⁶) = 6x⁸
Therefore, the polynomial is of 8th degree which means it has exactly 8 roots. This option is correct.
<u>B. (3x⁴+2x)⁴</u>
The term with the highest power will be (3x⁴)⁴ = 81x¹⁶
Therefore, the polynomial is of 16th degree which means it has exactly 16 roots. This option is incorrect.
<u>C. (4x²-7)³</u>
The term with the highest power will be (4x²)³ = 64x⁶
Therefore, the polynomial is of 6th degree which means that it has exactly 6 roots. This option is incorrect
<u>D. (6x⁸-4x⁵-1)(3x²-4)</u>
The term with the highest power will be (6x⁸)(3x²) = 18x¹⁰
Therefore, the polynomial is of 10th degree which means that it has exactly 10 roots. This option is incorrect
Hope this helps :)
I agree with the given answer because of the gain or loss on retirement of bonds = book value of bonds - the amount paid to the bondholders
Answer:
a) Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
b) If the true mean is 190 days, Type II error can be made.
Step-by-step explanation:
Let mu be the mean life of the batteries of the company when it is used in a wireless mouse
Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.
That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.
