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Harman [31]
1 year ago
7

Alec and Kiara went to Freddy's Yogurt Shop for frozen yogurt. Alec got 8.6 ounces of strawberry frozen yogurt, and Kiara got 8.

2 ounces of chocolate frozen yogurt. Their frozen yogurt cost $0.50 per ounce. How much did they pay in all?
Mathematics
2 answers:
lesya692 [45]1 year ago
8 0

Answer:

$8.40 Total

Step-by-step explanation:

Frozen yogurt costs $0.50 per ounce so the cost for Alec's is 8.6 ounces * $0.50 per ounce which is $4.30. Kiara is 8.2 ounces * $0.50 per ounce which is $4.10. The total is $4.30+$4.10 which is $8.40.

LiRa [457]1 year ago
6 0

Answer:

$8.40

Step-by-step explanation:

8.6 plus 8.2 is 16.8 so they had a total of 16.8 ounces.  $0.50 per ounce so you need to multiply 16.8 by 0.50 which is 8.40.  you can also do 8.6(0.5) plus 8.2(0.5)=  4.3 plus 4.1 = 8.4

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Step-by-step explanation:

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Ashley's Internet service is terribly unreliable. In fact, on any given day, there is a 25 % chance that her Internet connection
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Answer:

The probability that her internet service will not be broken for five days in a row is 243/1024

Step-by-step explanation:

Here, we want to calculate the probability that her internet service is not broken for five days in a row

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Thus, the probability that her internet is not broken for five days in a row = P(N) * P(N) * P(N) * P(N) * P(N)

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2 years ago
Mrs. Kermit has 29 markers. She gives 12 markers to Mr. Cooke and divides the rest among 5 other teachers. If each of the teache
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Answer: 2 markers.

Step-by-step explanation:

1. You know that she gives 12 markers to Mr. Cooke, then the rest among is:

29 markers-12 markers=17 markers

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Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st
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Answer:

a) The 95% confidence interval would be given by (509.592;550.308)  

b) n=523 rounded up to the nearest integer  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=530 represent the sample mean for the sample  

\mu population mean

s=70 represent the sample standard deviation  

n=48 represent the sample size (variable of interest)  

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that z_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

530-2.01\frac{70}{\sqrt{48}}=509.692  

530+2.01\frac{70}{\sqrt{48}}=550.308  

So on this case the 95% confidence interval would be given by (509.592;550.308)  

Part b

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (a)  

Assuming that \hat \sigma =s

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (b)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (b) we got:  

n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523  

So the answer for this case would be n=523 rounded up to the nearest integer  

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