Notice that
so the constraint is a set of two lines,
and only the first line passes through the first quadrant.
The distance between any point 
in the plane is 
, but we know that 
and 
share the same critical points, so we need only worry about minimizing 
. The Lagrangian for this problem is then
with partial derivatives (set equal to 0)
We have
which tells us that
so that 
is a critical point. The Hessian for the target function is
which is positive definite for all 
, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is 
.
They traveled 292 miles on day two.
Known: On the first day they traveled 365 and on the second they traveled 20% less.
Solution:
If they traveled 20% less on the second day, that means they traveled 80% of the distance they traveled the first day.
365 miles * .8 = 292.
You could also solve this as:
20% of 365 is 73 miles
365 * .2 = 73.
So they traveled 73 less miles on the second day.
365 miles on the first day - 73 miles less on the second day = 292 miles.
I hope this helps!
U would actually do both...because when ur dividing fractions, u end up multiplying....but u start with dividing.
6 / (1/3) =
6 * 3 = 18 <== ur answer
Answer:
y = 22.5 - 0.2t
Step-by-step explanation:
Given;
total number of candle, n = 22.5 ounce
Rate of candle burn, R = 1 ounce per 5 hours 
The amount of candle left = total initial value - amount burnt
let the amount let = y
y = 22.5 - 0.2t
where;
t is the time in which the candle is burnt
Thus, the equation for the amount of candle left is given by;
y = 22.5 - 0.2t
