Answer:
Step-by-step explanation:
For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.
We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The confidence interval for a proportion is given by this formula
For the 98% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution.
And the margin of error would be:
The reaction as an equation, using the abbreviation or the name of each two reactants and each of the three products is Adenosine Diphosphate + ATP = Pi.The equation in this question that use the name or the abbreviation is Adenosine Diphosphate + ATP = Pi. The answer in this question is Adenosine Diphosphate + ATP = Pi.
Hey :))
(-p,-q)(p,q)slope = (q - (-q) / (p - (-p) = (q + q) / (p + p) = 2q / 2p = q/p
y = mx + b.....slope(m) = q/p(p,q)...x = p and y = qnow we sub and find b, the y intq = (q/p)(p) + bq = q + bq - q = b0 = b
so ur equation is : y = (q/p)x + 0...or just y = (q/p)x....its answer B
HOPE THIS HELPED!!! :))
Answer:
a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)
=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363
hence probability that it actually contains explosives given identified as containing explosives)
=(10/(4*106))*0.95/0.005002363=0.000475
b)
let probability of correctly identifying a bag without explosives be a
hence a =0.99999763 ~ 99.999763%
c)
No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,
Answer:
0.45 part of the banner is painted orange
Step-by-step explanation:
portion of rectangular banner painted green = 0.75
Portion of green painted part which is now painted orange = 0.60
Hence we can say that
0.6 part out of 0.75 part of total banner is painted orange
mathematically it is
0.6 * 0.75 = 0.45
Thus 0.45 part of banner is painted orange .
