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tatyana61 [14]
2 years ago
15

Which function has no horizontal asymptote? F (x) = StartFraction 2 x minus 1 Over 3 x squared EndFraction f (x) = StartFraction

x minus 1 Over 3 x EndFraction f (x) = StartFraction 2 x squared Over 3 x minus 1 EndFraction f (x) = StartFraction 3 x squared Over x squared minus 1 EndFraction
Mathematics
2 answers:
Oduvanchick [21]2 years ago
8 0

Answer:

f(x)=\frac{2x^2}{3x-1}

Step-by-step explanation:

The function   has a horizontal asymptote which is

The function   has a horizontal asymptote which is

The function   has no horizontal asymptote  because the numerator has a degree which is higher than the degree of the denominator,

yanalaym [24]2 years ago
3 0

Answer:

f(x)=\frac{2x^2}{3x-1}

Step-by-step explanation:

The function  f(x)=\frac{2x-1}{3x} has a horizontal asymptote which is y=\frac{2}{3}

The function  f(x)=\frac{x-1}{3x} has a horizontal asymptote which is y=\frac{1}{3}

The function  f(x)=\frac{2x^2}{3x-1} has no horizontal asymptote  because the numerator has a degree which is higher than the degree of the denominator,

The function  f(x)=\frac{3x^2}{x^2-1} has a horizontal asymptote which is y=3

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OverLord2011 [107]

Answer:

Volume = 16 unit^3

Step-by-step explanation:

Given:

- Solid lies between planes x = 0 and x = 4.

- The diagonals rum from curves y = sqrt(x)  to  y = -sqrt(x)

Find:

Determine the Volume bounded.

Solution:

- First we will find the projected area of the solid on the x = 0 plane.

                              A(x) = 0.5*(diagonal)^2

- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,

                              A(x) = 0.5*(sqrt(x) + sqrt(x) )^2

                              A(x) = 0.5*(4x) = 2x

- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:

                              V = integral(A(x)).dx

                              V = integral(2*x).dx

                               V = x^2

- Evaluate limits 0 < x < 4:

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2 years ago
What is the range of the exponential function shown below
Vsevolod [243]

Answer : y>0

f(x) = 9*2^x

f(x) is an exponential function

f(x) = 9*2^x

When we plug in positive value for x , the value of y is positive

When we plug in negative value for x , the value y is also positive

So for any value of x, the y value is positive always.

Range is the set of y values for which the function is defined

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cluponka [151]

Answer:

x = 31 hundred dolars   and      

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Step-by-step explanation:

Given

R(x) = (40−8x+5y)*x + (50+9x−7y)*y

C(x) = (40−8x+5y)*10 + (50+9x−7y)*29

We can use the equation

P(x) = R(x) - C(x)

where

P(x) is the profit

R(x) is the revenue

and C(x) is the costs

In order to maximize the telephone company's profit, we apply

P'(x) = R(x)' - C(x)' = 0

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we get the solution

x = 31     and       y = 91/2 = 45.5

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