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Nana76 [90]
2 years ago
7

Divide 60 kg in the ratio of 5 : 7.

Mathematics
2 answers:
CaHeK987 [17]2 years ago
6 0
The ratio can be written in parts as shown below;
\frac{5}{12} : \frac{7}{12}
Then, 60 can be divided as shown below;
\frac{5}{12} *60: \frac{7}{12} *60
25kg:35kg
taurus [48]2 years ago
4 0
When we divide a number by a fraction, the turn-out is that we multiply the number to the reciprocal of the fraction. In this case, we are given with 60 kg and a fraction of 5/7. The product is equal to 60 kg * (7/5) equal to 84 kg. kg is remained uncanceled
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The answer is B because she threw those into the cart in the checkout line.
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2 years ago
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How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x
Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

\dfrac{1}{2}(x+12)=4x-1

Multiply this equation by 2:

2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)

Use distributive property:

x+12=8x-2

Combine the like terms:

x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2

Thus, this equation has one solution x = 2

7 0
2 years ago
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Accident rate data y1, ...., y12 were collected over 12 consecutive years t=1,2,...12. At over 12 consecutive years t = 1,2,...,
e-lub [12.9K]

Answer:

The correct option is;

The accident rate is a linear model function of t. After t = 7, the slope changes, with the two lines intersecting at t = 7

Step-by-step explanation:

The given parameters are;

Accident rate data = y₁, y₂, y₃, y₄, y₅, y₆, y₇, y₈, y₉, y₁₀, y₁₁, y₁₂

Time at which data was recorded = t₁, t₂, t₃, t₄, t₅, t₆, t₇, t₈, t₉, t₁₀, t₁₁, t₁₂

Accident rate equation is a linear model given as follows;

y = X·B + E

Where:

y = Accident rate

X = Slope of linear model

B = Year

E = y intercept of model

At the end of the 6th year, a change in a regulation that affects safety, hence accident rate occurred given as follows;

Before the change in safety regulations occurred for year t < 7 y₁ = X₁B + E₁

After the change in safety regulations occurred for year t < 7 y₂ = X₂B + E₂

Therefore the slope changes from X₁ to X₂ after t = 7 with the second linear model starting from the end of the first linear model making the two lines intersect at t = 7 (the beginning of year 7)

Hence the correct option is that "The accident rate is a linear model function of t. After t = 7, the slope changes, with the two lines intersecting at t = 7."

4 0
2 years ago
If x3=64 and y3=125, what is the value of y−x?
Verdich [7]

Answer:First we use equation 1

x=64/3

Second we solve equation 2

y=125/3

Now combine equation 1 and 2

y-x=125/3 -64/3

=61/3

Step-by-step explanation:

3 0
2 years ago
Which division expression is equivalent to 4 and one-third divided by Negative StartFraction 5 over 6 EndFraction? StartFraction
Kruka [31]

Answer:

  \dfrac{\left(\dfrac{13}{3}\right)}{\left(-\dfrac{5}{6}\right)}

Step-by-step explanation:

The first step is to convert the mixed number to an improper fraction.

  \dfrac{4\frac{1}{3}}{\left(-\dfrac{5}{6}\right)}=\boxed{\dfrac{\left(\dfrac{13}{3}\right)}{\left(-\dfrac{5}{6}\right)}}

6 0
2 years ago
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