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storchak [24]
2 years ago
5

To babysit one child, Fernando charges $10 to drive to the appointment plus $4 per hour. He saves 30% of the total amount he ear

ns. Brenna charges $6 per hour and saves 25% of the total amount she earns. Which equation can be used to determine the number of hours, h, after which Fernando and Brenna will have saved the same amount of money?
Mathematics
2 answers:
Kazeer [188]2 years ago
4 0
Answer: 10 hours

Explanation:

1) Fernando's earnings:

10 + 4h ← 10 is a fix charge, h is the number of hours and 4 is the rate per hour

2) Fernando's savings

0.30 (10 + 4h) ← 30% = 30 / 100 = 0.3

3 + 1.2h ← distributive property

3) Brenna's earnings

6h ← h is the number of hours, 6 is the rate per hour

4) Brenna's savings

0.25(6h) ← 25% = 25/100 = 0.25

1.5h ←0.25 × 6 = 1.5

5) Equal savings

3 + 1.2h = 1.5h

1.5th- 1.2h = 3 ← transpose terms

0.3h = 3 ← combine like terms

h = 3 / 0.3 = 10 ← divide by 0.3

Answer: h = 10
umka2103 [35]2 years ago
4 0

Answer:

(C) 0.3(10 + 4h) = 0.25(6h)

Plz press the <u>THANKS </u>button.

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irinina [24]

Given the points H(6,7) and I(-7,-6).

If point G lies \frac{1}{2} of the way along line segment HI.

Therefore, we can say that the point G divides the line segment HI in the ratio 1:1.

So, by using the cross section formula we can determine the coordinates of point G.

For the given points say (x_1, y_1) and (x_2, y_2) divided is in the ratio m_1 : m_2, the coordinates are (\frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} )

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So, Santiago argues that point G is located at the origin. The point G is located at (-0.5, 0.5). Therefore, he is not correct.

8 0
2 years ago
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MArishka [77]
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Math Question: Your Team is given a bag containing a set of colored blocks or counters. The bag contains 5 yellow, 1 red, 6 green, and 8 blue blocks. If you were to reach into the bag and select one block without looking what is the probability of selecting a yellow block and the probability of selecting a green
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Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o
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Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2} * Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71

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[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485

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[121.96; 185.60]

I hope this helps!

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Answer:

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