We are asked to solve for:
P (sand | positive)
So, we solve this by:
P (sand | positive) = P (sand) x P (positive for sand)
P (sand | positive) = 0.26 (0.75)
P (sand | positive) = 0.195
The probability is 0.195 or 19.5%.
Answer:
Part A)
x+y=80
y=x+20
B)
30 minutes
C)
no
If Pam was to spend 60 minutes practicing dance, then she would only get 20 minutes of math. 60-20=40. She would be practicing dance 40 minutes more than math, not just 20.
Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
P(A U B U C) = 0.53
4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
case 1,
Let the CP be ₹x,
SP = ₹2400
Profit = SP – CP
= 2400 – x
Profit % = {(2400–x)/ x} × 100%
According to the question,
{(2400–x)/ x} × 100 = 25
=> (2400–x)/ x= 25 /100
=> 100(2400–x) = 25x [ cross multiplication]
=> 240000 – 100x = 25x
=> 240000 = 25x + 100x
=> 240000 = 125x
=> 240000/125 = x
=> x = 1920
So, CP = ₹1920
case 2,
SP = ₹2040
Profit = SP – CP
= 2040 – 1920
= ₹120
profit % = 120/1920 × 100%
= 16%
<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>
