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Elenna [48]
2 years ago
13

Sina played basketball on a rectangular court that was 74 feet by 42 feet. after the game, she walked across the court diagonall

y from one corner to the opposite corner. approximately what distance did sina walk in feet?
Mathematics
2 answers:
Butoxors [25]2 years ago
8 0

Distance walked = 85.088 feet


The distance Sina walked would be equal to the length of the diagonal of rectangle.

As every angle in a rectangle is 90 degree. So, we can apply Pythagoras theorem in right triangle formed by sides,

Base- 74 feet, Altitude-  42 feet and Hypotenuse- Diagonal

Base^2 + Altitude ^ 2 = Hypotenuse ^2

74^2 + 42 ^ 2 = Diagonal ^2

On solving,

Diagonal = 85.088 feet

Naddika [18.5K]2 years ago
6 0
the distance Sina walked was 7,240 feet
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