Answer:
(a) 
(b)
Step-by-step explanation:
(a)
Let u = π x
differentiating with respect to x
du = π dx
Putting the value of x and dx
[ c is an arbitrary constant]
Now putting the value of u
(b)
Let 
differentiating with respect to x
2du = dx
Putting the value of x and dx
=
=
Now putting the value of u
[ c is an arbitrary constant]
5x=25 could be one.
25/x-3=2 is another.
And the last one could be x/85+7=24
9514 1404 393
Answer:
A. A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2
Step-by-step explanation:
The relationship that has constant y-values is the one with zero slope. That would be the first table.
From the given above, we will include the case in which 3 and all 4 defectives are included in the purchase.
For 3:
(36C5) x (4C3) = 1507968
For 4:
(36C4) x (4C4) = 58905
Adding these numbers will give us an answer of 1566873.
Let the total sum of the scores of the first class of 35 students be
a. The mean is 74.3
.
So
Also, let the total sum of the scores of the second class of 28 students be
b. The mean is 67.6 .
so
The combined group has 35+28=63 students. The sum of their scores is
a+b=2600.5+1892.8=4493.3
Thus, the mean of the combined group is
