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Archy [21]
1 year ago
8

Use the drop-down menus to choose steps in order to correctly solve 4k−6=-2k−16−2 for k .

Mathematics
1 answer:
Triss [41]1 year ago
8 0
While there is no drop-down menu options for me to choose. I will show you how to solve this.

\mathrm{Subtract\:the\:numbers:}\:-16-2=-18 \ \textgreater \  4k-6=-2k-18

\mathrm{Add\:}6\mathrm{\:to\:both\:sides} \ \textgreater \  4k-6+6=-2k-18+6 \ \textgreater \  Simplify

4k=-2k-12 \ \textgreater \  \mathrm{Add\:}2k\mathrm{\:to\:both\:sides} \ \textgreater \  4k+2k=-2k-12+2k

Simplify again.

6k=-12 \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}6 \ \textgreater \  \frac{6k}{6}=\frac{-12}{6} \ \textgreater \  Simplify \ \textgreater \  k=-2

Hope this helps!
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