In a camp there is food for 400 persons for 23 days-if 60 more persons join the camp find the number of days the provision will
1 answer:
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Answer:
The median and mode of the students grade is 70.
Most of the students scored between 40 and 100.
Step-by-step explanation:
From the provided information it can be seen that the mean of the distribution is, <em>μ</em> = 70 and the standard deviation is, <em>σ</em> = 15.
For a Normal distributed data the mean, median and mode are the same.
So, the median and mode of the students grade is 70.
The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.
In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.
Assuming that maximum marks of the exam is 100, it can be said that most of the students scored between 40 and 100.
Answer:
In Right Δ ABC with right angle B,
∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°
∠A+∠B+∠C=180°[∠ sum property of triangle]
3 x-8+90 + x-2=180
Adding and subtracting like terms
4 x-10+90=180
4 x+80=180
4 x=180-80
4 x=100
x=100/4
x=25°
∠A=3×25-8=75-8=67°
Answer:
-1.14
Step-by-step explanation:
The given information in statement is
mean=μ=69
standard deviation=σ=3.5
Let X be the Ishaan's exam score
X=65
The Z score can be computed as
z=-1.1429
z=-1.14 (rounded to two decimal places).
Thus, the computed z-score for Ishaan's exam grade is -1.14.