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kenny6666 [7]
2 years ago
7

Which graph matches the equation y+3=2(x+3)?

Mathematics
1 answer:
Vlad1618 [11]2 years ago
8 0

Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

y+3=2(0+3)

y+3 = 6

y = 6 - 3

y = 3

Then, point (0, 3) is on the line.

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Positive 14/472 (because of rise over run when finding slope)
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How to round 47,125 to the nearest ten,to the nearest hundred, to the nearest thousand and to the nearest ten thousand
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To be able to round the number 47,125 to the nearest tenth, hundredth, and thousandth place you need to know were those places are. The tens place is the second one from the right hand side. The hundreds place is the third one from the right hand side and the thousands place is the one right after the comma. Now, to round to the tens place, you need to look at the place right behind it (which would be the ones place) then you need to analyze. If the number in the ones place is between 0-4 you can NOT round the tens place but, if it is between 5-9 you can. The same rule applies when you round to the hundreds and thousands place. So the number you should end up with is - 47,135. 
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You count customers going into the 5 pizza shops in your city. You get 56, 98, 43, 112, and 106. What is the median number of cu
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2 years ago
Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?
SCORPION-xisa [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?

A. (-6, 0)

B. (0, -6)

C. (0, 2)

D. (2, 0)

The graph of the question is attached.

Answer:

The point is (x, y) = (0, 2)

The correct option is C.

Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.

Step-by-step explanation:

From the given graph, the points A and B are

(x_1, y_1) = (-2, 4) \\\\(x_2, y_2) = (2,-8) \\\\

The slope of the equation is given by

m_1 = \frac{-8 - 4 }{2 -(-2)} \\\\ m_1 = \frac{-12 }{2+2} \\\\m_1 = \frac{-12 }{4} \\\\m_1 = -3 \\\\

We know that the slopes of two perpendicular lines are negative reciprocals of each other.

m_2 = - \frac{1}{m_1}

So the slope of the other line is

m_2 = \frac{1 }{3} \\\\

Now we can find the equation of the line that is perpendicular to the line AB and passes through the point C.

From the graph, the coordinates of point C are

(x_1, y_1) = (6, 4)

The point-slope form is given by,

y - y_1 = m(x -x_1)

Substitute the value of slope and the coordinates of point C

y - 4 = \frac{1 }{3} (x - 6)\\\\

To get the y-intercept, substitute x = 0  

y - 4 = \frac{1 }{3} (0 - 6) \\\\y - 4 = \frac{-6 }{3}\\\\y - 4 = -2\\\\y = 4 -2 \\\\y = 2 \\\\

So, the point is

(x, y) = (0, 2)

The correct option is C.

Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.

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Answer:

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Step-by-step explanation:

we know that

sin(\alpha)=cos(\beta)

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so

sin(30\°)=cos(60\°)

sin(60\°)=cos(30\°)

Because

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In this problem the product of

sin(30\°)*sin(60\°)

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sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

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