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Lina20 [59]
2 years ago
14

Tyrell's SAT math score was in the 64th percentile. If all SAT math scores are normally distributed with a mean of 500 and a sta

ndard deviation of 100, what is Tyrell's math score? Round your answer to the nearest whole number
Mathematics
1 answer:
jarptica [38.1K]2 years ago
8 0

Answer:

P(x < 535.8) = 0.64

P_{64} = 535.8

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.64

P(X<x) = 0.64

P( X < x) = P( z < \displaystyle\frac{x - 500}{10})=0.64  

Calculation the value from standard normal z table, we have,  p(z

\displaystyle\frac{x - 500}{100} = 0.358\\x = 535.8

P(x < 535.8) = 0.64

P_{64} = 535.8

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Sally is planning a trip for 225 students
Gala2k [10]

Answer: 75 students.

Step-by-step explanation:

In the data set we have a total of 10 + 8 + 7 + 5 = 30 students.

of those, 10 want to go to the park, the percentage is:

(10/30)*100% = 33.3%

Then, out of the 225, we can expect that a 33.3% (or 0.333 in decimal form) want to go to the park, this is:

N = 225*0.333% = 74.925

We can roud it up, and get N = 75

So Sally can expect that 75 students want to go to the park

4 0
2 years ago
Mr. Peterson needs topsoil for his garden. His rectangular garden is 78 in long and 48 in wide. A bag of topsoil covers an area
nata0808 [166]

Answer:

3744 inches squared, and 8 bags

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

˜”*°•.˜”*°• Area: •°*”˜.•°*”˜

Well, the formula for area is L*W

L=78 inches

W=48 inches

78*48=3744 inches squared

˜”*°•.˜”*°• Number of bags: •°*”˜.•°*”˜

3744/500=7.448

So he would need to buy 8 bags

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

4 0
2 years ago
r Flag For Review A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to h
Alex787 [66]

Answer:

P = \frac{132000}{12}=11000

So then P =11000 is the minimum that the least populated district could have.

Step-by-step explanation:

We have a big total of N = 132000 for the population.

And we know that we divide this population into 11 districts

And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"

Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P

The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:

P + 10 (1.1P) = 12 P= 132000

P = \frac{132000}{12}=11000

So then P =11000 is the minimum that the least populated district could have.  

3 0
2 years ago
Justin is working two summer jobs, making $8 per hour babysitting and $14 per hour lifeguarding. Last week Justin earned a total
alexdok [17]

Answer:

Justin worked as a babysitter  8 hours and worked as a lifeguard 2 hours last week

Step-by-step explanation:

Let

x ----> number of hours worked as a babysitter  last week

y ----> number of hours worked as a lifeguard last week

we know that

8x+14y=92 ----> equation A

x=4y ----> equation B

Solve the system by substitution

Substitute equation B in equation A

8(4y)+14y=92

solve for y

32y+14y=92

46y=92

y=2

Find the value of x

x=4(2)=8

therefore

Justin worked as a babysitter  8 hours and worked as a lifeguard 2 hours last week

6 0
2 years ago
A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between
Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

y(x) = 25,000*0.95^x

In the first year the value of the printer is:

y(1) = 25,000*0.95^1 = 23,750

On the second year the value of the printer is:

y(2) = 25,000*0.95^2 = 22,562.5\\

On the third year the value of the printer is:

y(3) = 25,000*0.95^3 = 21,434.38\\

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0
2 years ago
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