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Scorpion4ik [409]
2 years ago
10

Answer the following questions based on what you know about the points of concurrency.

Mathematics
1 answer:
svetlana [45]2 years ago
3 0
Part1:
The answer is "circumcenter".

One of a few centers the triangle can have, the circumcenter is where the perpendicular bisectors of a triangle converge or intersect. The circumcenter is additionally the focal or central point of the triangle's circumcircle - the circle that goes through each of the three of the triangle's vertices. 

Part2:
The answer is "centroid".

The centroid of a triangle refers to the intersection point of the three medians of the triangle (every median associating a vertex with the midpoint of the contrary side). It lies on the triangle's Euler line, which additionally experiences different other key focuses including the orthocenter and the circumcenter. 

Part3;
The answer is "incenter".

The incenter of a triangle refers to a triangle center, a point characterized for any triangle in a way that is free of the triangle's situation or scale. The incenter might be identically characterized as the point where the interior edge bisectors of the triangle cross, as the point equidistant from the triangle's sides, as the intersection purpose of the average pivot and deepest purpose of the grassfire change of the triangle, and as the inside purpose of the inscribed circle of the triangle.
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I would like to purchase 20 products at the cost of $65 per product the state sales tax is 3.5% what is the total
Ivanshal [37]
1,650 is the answer to your question
7 0
2 years ago
Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v
Bumek [7]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

A

is dimensionally consistent

B

is not dimensionally consistent

C

is dimensionally consistent

D

is not dimensionally consistent

E

is not dimensionally consistent

F

is dimensionally consistent

G

is dimensionally consistent

H

is not dimensionally consistent

Step-by-step explanation:

From the question we are told that

   The equation are

                        A) \   \  a^3  =  \frac{x^2 v}{t^5}

                       

                       B) \   \  x  =  t

 

                       C \ \ \ v  =  \frac{x^2}{at^3}

 

                      D \ \ \ xa^2 = \frac{x^2v}{t^4}

                      E \ \ \ x  = vt+ \frac{vt^2}{2}

                     F \ \ \  x = 3vt

 

                    G \ \ \  v =  5at

 

                    H \ \ \  a  =  \frac{v}{t} + \frac{xv^2}{2}

Generally in dimension

     x - length is represented as  L

     t -  time is represented as T

     m = mass is represented as M

Considering A

           a^3  =  (\frac{L}{T^2} )^3 =  L^3\cdot T^{-6}

and    \frac{x^2v}{t^5 } =  \frac{L^2 L T^{-1}}{T^5}  =  L^3 \cdot T^{-6}

Hence

           a^3  =  \frac{x^2 v}{t^5} is dimensionally consistent

Considering B

            x =  L

and      

            t = T

Hence

      x  =  t  is not dimensionally consistent

Considering C

     v  =  LT^{-1}

and  

    \frac{x^2 }{at^3} =  \frac{L^2}{LT^{-2} T^{3}}  =  LT^{-1}

Hence

   v  =  \frac{x^2}{at^3}  is dimensionally consistent

Considering D

    xa^2  = L(LT^{-2})^2 =  L^3T^{-4}

and

     \frac{x^2v}{t^4}  = \frac{L^2(LT^{-1})}{ T^5} =  L^3 T^{-5}

Hence

    xa^2 = \frac{x^2v}{t^4}  is not dimensionally consistent

Considering E

   x =  L

;

   vt  =  LT^{-1} T =  L

and  

    \frac{vt^2}{2}  =  LT^{-1}T^{2} =  LT

Hence

   E \ \ \ x  = vt+ \frac{vt^2}{2}   is not dimensionally consistent

Considering F

     x =  L

and

    3vt = LT^{-1}T =  L      Note in dimensional analysis numbers are

                                                       not considered

  Hence

       F \ \ \  x = 3vt  is dimensionally consistent

Considering G

    v  =  LT^{-1}

and

    at =  LT^{-2}T =  LT^{-1}

Hence

      G \ \ \  v =  5at   is dimensionally consistent

Considering H

     a =  LT^{-2}

,

       \frac{v}{t}  =  \frac{LT^{-1}}{T}  =  LT^{-2}

and

    \frac{xv^2}{2} =  L(LT^{-1})^2 =  L^3T^{-2}

Hence

    H \ \ \  a  =  \frac{v}{t} + \frac{xv^2}{2}  is not dimensionally consistent

8 0
2 years ago
Analyze the diagram to complete the statements. The m∠MXN is the m∠YZX. The m∠LZX is the m∠ZYX + m∠YXZ. The m∠MYL is 180° − m∠ZY
Xelga [282]

By using the picture that was provided below, you can see that

m<MXN is greater than m<YZX.  

Angles m<LZX is equal to m<ZYX + m<YZX and

m<MYL is equal to 180 degrees minus M<ZYX.


I hope this helps! Have a good day


8 0
2 years ago
Read 2 more answers
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1863 mailboxes t
worty [1.4K]

Answer:

3433 m²

Step-by-step explanation:

From the image, we have a rectangular box without cover and half a cylinder on top.

Formula for surface area of rectangular box with top is;

S = 2(lh + wh + lw)

From the image,

l = 0.6 m

w = 0.4 m

h = 0.55 m

Thus;

S = 2((0.6 × 0.55) + (0.4 × 0.55) + (0.6 × 0.4))

S = 1.58 m²

Now, since the top is not included for this figure, then;

Surface area of this rectangular box is;

S1 = 1.58 - (lw) = 1.58 - (0.4 × 0.6) = 1.34 m²

Surface area of a cylinder is;

S = 2πr² + 2πrh

r is radius and in this case = 0.4/2 = 0.2 m

h = 0.6

S = 2π(0.2² + (0.2 × 0.6))

S = 1.005 m²

Since it is half cylinder, then we have;

S2 = 1.005/2

S2 = 0.5025 m²

Total surface area; S_t = S1 + S2

S_t = 1.34 + 0.5025

S_t = 1.8425 m²

This is the surface area of one mail box.

Thus, for 1863 mailboxes, total surface area is;

S = 1863 × 1.8425 = 3432.5775 m²

Approximating to the nearest Sq.m gives;

S = 3433 m²

6 0
2 years ago
Researchers recorded that a group of bacteria grew from 100 to 7,000 in 14 hours. At this rate of growth, how many bacteria will
Alik [6]

The number of bacteria grown in 32 hours is 15771

<u>Step-by-step explanation:</u>

It is given that,

Researchers recorded that a group of bacteria grew from 100 to 7,000 in 14 hours.

Therefore, the bacteria has grown from 100 to 7000 in 14 hours.

<u> To calculate number of bacteria grown in 14 hours :</u>

⇒ 7000 - 100 = 6900

6900 bacteria grows in 14 hours. We need to find out the growth of bacteria in 1 hour in order to calculate its growth in 32 hours.

<u>To calculate number of bacteria grown in 1 hour :</u>

⇒ Total bacteria growth in 14 hours / 14

⇒ 6900 / 14

⇒ 492.85

<u>To calculate number of bacteria grown in 32 hours :</u>

⇒ 492.85 × 32

⇒ 15771.2

⇒ 15771  (rounded to nearest whole number)

∴ The number of bacteria grown in 32 hours is 15771

6 0
2 years ago
Read 2 more answers
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