9514 1404 393
Answer:
(x +6)^2 +(y -4)^2 = 36
Step-by-step explanation:
The center is (-6, 4) and the radius is 6. Putting those into the standard form equation, you have ...
(x -h)^2 +(y -k)^2 = r^2 . . . . . . center (h, k), radius r
(x -(-6))^2 +(y -4)^2 = 6^2 . . . . numbers filled in
(x +6)^2 +(y -4)^2 = 36 . . . . . . cleaned up a bit
Answer: C) For every original price, there is exactly one sale price.
For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.
As the table shows, we do not have any repeated original prices leading to different sale prices.
Omari (3 1/2)___________(0)school____________(3 1/4)daisy
3 1/2 + 3 1/4 = 6 + (1/2 + 1/4) = 6 + (2/4 + 1/4) = 6 3/4 blocks apart <==
Answer:
x = 9
Step-by-step explanation:
The trick here is knowing that JKM and MKL are equal, which means MKL is equal to JKL/2. From that knowledge, we can solve.
MKL = JKL/2
5x + 1 = 46
5x = 45
x = 9
The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t
