Answer:
See Explanation
Step-by-step explanation:
Incomplete question, as the number line is not attached. However, the solution is as follows:
Let y be the absolute value of -1/2 So:
The absolute sign removes all negation. So:
This means that the point at the label or
is the solution to the question.
<em>Take for instance, the attached image has point Q at </em><em>.</em>
<em>Hence, Q is the absolute value of -1/2</em>
<em />
Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.
(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.
Step-by-step explanation:
Given that,
Height (in inches) of a 25 year old man is a normal random variable with mean and variance
.
To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall
(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.
Now,
(a) To calculate the percentage of men, we have to calculate the probability
P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>]
P[X>74] = P[ >
]
= P[Z > 1.2]
= 1 - P[Z ≤ 1.2]
= 1 - Ф (1.2)
= 1 - 0.8849
= 0.1151
Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.
(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X,
- X,
]
P[X >
I X >
] = P[X > 77 I X > 72]
=
=
=
=
=
=
= 0.024
Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.
Answer:
69.3 mi
Step-by-step explanation:
Let x represent the distance of the ship from its original position.
x²= 40² + 35² -2(40)(35)cos(135)
x= 69.3 mi