Sandra Leatherwood invested money received from a game show for 10 months at 9% interest.

A researcher found a study relating the value of a car, y, to the age of the car, x. When researchers looked at the association

vredina [299]

Answer: c) About 16% of the variation in value of the car is explained by a linear relationship with the age of the car.

e) The correlation coefficient, r, is 0.397.

Step-by-step explanation:

Given that:

Coefficient of determination (r²) between two variables, age of car (x) and value of car (y) = 0.158

Correlation of determination (r²) of 0.158 = (0.158 × 100% = 15.8% of the variation between the two variables can be explained by the regression line). Hence, about 16% of the variation between age and value of car can be explained by the linear relationship.

Coefficient of correlation (r) = sqrt(r²) = sqrt(0.158) = 0.397

8 0

2 years ago

A certain small factory employs 98 workers of these 10 recieve a wage of 150 dollars per day and the rest recieve 85.50 dollars

cricket20 [7]

10 × $150 = $1500
88 × $85.50 = $7524
1500 + 7524 = $9024 a day.
9024 × 6 = $54,144 (the answer)
Hope this helps!

4 0

1 year ago

Read 2 more answers

What is the greatest whole number that will divide both 792 and 990 exactly

Nastasia [14]

Factor the numbers, starting from the smallest:
792=2*3*3*11*4
990=2*3*3*11*5
the greatest whole number that can be divided by both 792 and 990 is 2*3*3*11=198
the smallest whole number that can divide both 792 and 990 exactly is 2*3*3*11*4*5=3960

Not sure which one you are asked to find.

8 0

2 years ago

Read 2 more answers

Help me with this question!!!

qwelly [4]

Step-by-step explanation:

×=100

1. Divded 35 by 14 and u get 0.4

2

Divided 40 by 0.4 and u get 100

6 0

2 years ago

Read 2 more answers

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

5 0

2 years ago