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slavikrds [6]
2 years ago
6

Benjamin bought tokens at a funfair.he used 3out if 8 of them at the ring toss booth and 2out of5 of the remaining tokens at the

darts booth he then bought another 35 and had 10 tokens more then what he had at first how many tokens did he have at first
Mathematics
1 answer:
Daniel [21]2 years ago
3 0

Let's assume he bought "x" tokens initially.

He spent 3 over 8 of them at ring toss game booth. So he used (3x/8) tokens there.

His remaining tokens after first game = x - (3x/8) = (5x/8) tokens.

He then spent 2 over 5 of them at darts game booth. So he spent (2/5)(5x/8) = (x/4) tokens there.

His left over tokens after second game = (5x/8) - (x/4) = (3x/8) tokens.

Now he bought another 35 tokens, his new balance = 35 + (3x/8)  tokens.

His new balance is ten more than his initially bought tokens.

So 35 + (3x/8) - x = 10

35 + (3x-8x)/8 = 10

35 + (-5x/8) = 10

(5x/8) = 35 - 10

(5x/8) = 25

5x = 25*8 = 200

x = 200/5 = 40

Hence, he bought initially 40 tokens.

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Kara starts tying a baby quilt at the local community center. Each quilt takes 200 ties to complete. Ten minutes later Julie joi
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Answer:

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

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Step-by-step explanation:

Data

Kara_{(K)}=6\frac{tie}{min}\\Julie(J)=11\frac{tie}{min}

Kara begins ten minutes before julie, so when julie joins kara she has 60 ties

t=10 k=6\frac{tie}{min}*10min=60tie

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

c)T_{f}(t)=K(t+10)+J(t) where T_{f}(t)= number ties finished per unit time

d) if kara already has 60 ties and makes 6 per minute and Julie makes 11 per minute then per minute they makes 17 ties, so one minute per 17 ties for 200 ties ¿how long?. t=\frac{(200-60)tie*min}{17tie}≅8.24min

e) K=60tie+6tie/min*8.24min=109tie

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