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Rudik [331]
1 year ago
7

The low temperatures in two cities are being compared. In City 1, the range in temperature is 20°F and the IQR is 7°F. In City 2

, the range in temperature is 15°F and the IQR is 7°F. What might you conclude about the cities based on the ranges and interquartile ranges?
A. The weather patterns in City 1 and City 2 are equally consistent.
B. The weather pattern in City 2 is more consistent than the weather pattern in
City 1.
C. The weather pattern in City 1 is more consistent than the weather pattern in
City 2.
D. There is not enough information to make a conclusion
Mathematics
2 answers:
Tomtit [17]1 year ago
5 0
I wanna say (C) would be your best bet correct me if I’m wrong
ruslelena [56]1 year ago
3 0

Answer:

B. The weather pattern in City 2 is more consistent than the weather pattern in  City 1.

Step-by-step explanation:

Range and Interquartile range(IQR) measures the spread of data. Range measure the overall spread and IQR measures spread in 50% of data.

Range is calculate by difference of maximum and minimum value whereas IQR is calculated by difference of First quartile and third quartile.

<em>Since, the Range and IQR is less for City 2 as compared to City 1. </em>

<em>Thus, weather pattern of City 2 is more consistent as compared to City 1.</em>

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The answer to this one is d
6 0
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Jacob has a bag of his favorite marbles. It has 3 red marbles, 4 blue, and 10 of his most favorite color, neon orange. What is t
drek231 [11]

Answer:

P(1\ and\ 2) = 0.3309

Step-by-step explanation:

Given

Red = 3

Blue = 4

Orange=10

Required

Probability of selecting 2 orange marbles

The total number of marbles is:

Total = Red + Blue + Orange

Total = 3 + 4 + 10

Total = 17

The probability that the first selection is orange is:

P(1) = \frac{10}{17}

Because it is a selection without replacement, the number of orange marbles and the total number of marbles would decrease by 1, respectively.

So, the probability that the selection is orange is:

P(2) = \frac{10-1}{17-1}

P(2) = \frac{9}{16}

The required probability is:

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P(1\ and\ 2) = \frac{10}{17} * \frac{9}{16}

P(1\ and\ 2) = \frac{10*9}{17*16}

P(1\ and\ 2) = \frac{90}{272}

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7 0
1 year ago
The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

P'(t) = $3 per day RATE OF CHANGE  

the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

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P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

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P(t) = $28 per share close price



4 0
1 year ago
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We are given the equation:

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Substituting this value into equation # 1:

Z = 4 (u + ½) + ½ = z (u + 1/2) 

4 u + 2 + ½ = z (u + 1/2) 

<span>Since it was given that   z (u + 1/2)  = ½     then,</span>

4 u + 2 + ½ = ½

4 u + 2.5 = 0.5

4 u = -2

u = -1/2         (ANSWER)

 

 

<span> </span>

5 0
2 years ago
a guy wire makes a 67 degree angle with the ground. walking out 32 ft further grom the tower,the angle of elevation to the top o
Shalnov [3]

Answer:

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Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between angles and sides of a right triangle.

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Solving the first equation for CD and using that in the second equation, we can get an equation for AD, the height of the tower.

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  32·tan(39°)tan(67°)/(tan(67°) -tan(39°)) = AD . . . . divide by AD coefficient

  AD ≈ 39.486 . . . . feet

The tower is about 39.5 feet high.

6 0
2 years ago
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