Answer:
18,354 - 4,672= 13,682
Step-by-step explanation:
I'm not sure what you meant but above is the answer of what I think you were asking.
Answer:
d. The average is equal to 12 ounces.
Step-by-step explanation:
In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:
The correct alternative is d. The average is equal to 12 ounces.
Answer:
0.99865
Step-by-step explanation:
The question above is modelled by gaussian distribution. Gaussian distribution is also known as Normal distribution.
To solve the above question, we would be using the z score formula
The formula for calculating a z-score
z = (x-μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
In the above question,
x is 115 liters
μ is 100
σ is the population standard deviation is unknown. But we were given variance in the question.
Standard deviation = √Variance
Variance = 9
Hence, Standard deviation = √9 = 3
We go ahead to calculate our z score
z = (x-μ)/σ
z = (115 - 100) / 3
z = 15/ 3
z score = 5
Using the z score table of normal distribution to find the Probability of having a z score of 5
P(x = 115) = P(z = 5) =
0.99865
Therefore the probability that this year it will produce 115 liters of wine = 0.99865
I'm pretty sure the answer will be 6/10
Hope this helps, best of luck, terribly sorry if I'm wrong if I am my apologies
~Animaljamissofab ♥
<span>The nearest perfect square that is less than 22 is 16, whose square root is 4.
</span><span>Add the square root from step 1 to 3/4 to get 4.75.
</span>Calculate the quantity one-half times the square of divided by the value found in step 2, or 4.75. (1/2 * (3/4)^2) <span>÷ 4.75 = 0.06.
</span>
Subtract the value found in step 3 from the value found in step 2, or 4.75.
The approximate value of <span>√22 is 4.69.</span>
