We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity
in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr
the answer is 47.88 g
The correct answer is the choice that you have selected, the third choice.
When, we are looking at the residuals for a regression line, we always want to see the points balance like in the third choice. This means that the equation that we found is right in the middle of the points.
From the table, the speed of Corinne is given by

From the graph, the speed of Aretha is given by

The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t
Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then
0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140
Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.
Part 1:
Given a number line with the point

and the point

The sampling error is given by:

Part 2:
Given a number line with the point

and the point

The sampling error is given by:
The is Answer:
82
Explanation:
We observe that difference between first and second terms <span>=12−5=7</span>
Similarly difference between second and third terms <span>=19−12=7</span>
It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.
We know that <span>nth</span> term of an AP whose first term is <span>a1</span> and whose common difference is d is given by
<span><span>an</span>=<span>a1</span>+<span>(n–1)</span>d</span>
To find the <span>12th</span> term, insert given values in the general expression
<span><span>a12</span>=5+<span>(12–1)</span>7</span>
<span><span>a12</span>=5+<span>(11)</span>7=5+77=<span>82</span></span>