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tatuchka [14]
2 years ago
11

Fertiliser is sold in 100kg bags labelled with the amount of nitrogen (N), phosphoric acid (P2O5), and potash (K2O) present. The

mixture of these nutrients varies from one type of fertiliser to the next. 1 bag of Vigoro Ultra Turf fertiliser contains 29kg of nitrogen, 3kg of phosphoric acid, and 4kg of potash. 1 bag of Parkers Premium Starter fertiliser contains 18kg of nitrogen, 25kg of phosphoric acid, and 6kg of potash. How many bags of Vigoro Ultra Turf and Parkers Premium Starter would you require in order to make a fertiliser mixture containing 217kg of nitrogen, 115kg of phosphoric acid, and 44kg of potash
Mathematics
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

Step-by-step explanation:

Let's first list the percentage compositions of each fertilizer type:

<u>Vigoro Ultra Turf:</u>

Nitrogen (N) = 29 kg

Phosphoric Acid (P2O5) = 3 kg

Potash (K2O) = 4 kg

<u>Parkers Premium</u>

Nitrogen (N) = 18 kg

Phosphoric Acid (P2O5) = 25 kg

Potash (K2O) = 6 kg

We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:

x = Vigoro Ultra turf (one bag)

y = Parkers Premium (one bag)

29x + 18y = 217   -Equation 1

3x + 25y = 115     -Equation 2

4x + 6y = 44        -Equation 3

Solving for x and y, we get:

x = 5

y = 4

This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

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In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
2 years ago
A restaurant sells 1,725 pounds of spaghetti and 925 pounds of linguini every month. After 9 months, how many pounds of pasta do
VladimirAG [237]
Situation: A restaurant sells 1 725 pounds of spaghetti and 925 pounds of linguini every months. Problem : Find the number of pounds of pasta does the restaurant sell in 9 months. => Pasta is also known as the sphaghetti. And since the restaurant sells 1 725 pounds every month, simply multiply this number by 9 to get the total amount of pounds in 9 months. => 1 725 * 9 = 15 525 pounds in 9 months.
7 0
2 years ago
Read 2 more answers
A company makes 150 bags.
irina [24]
35% chance because the company made 150 bags
4 0
1 year ago
The average life of a bread-making machine is 7 years, with a standard deviation of 1 year. Assuming that the lives of these mac
Alina [70]

Answer:

a) P(6.4

b) a=7 +1.036*0.333=7.345

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable life of a bread making machine. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =7,\sigma =1)

We take a sample of n=9 . That represent the sample size.

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=7, \frac{1}{\sqrt{9}})

Solution to the problem

Part a

(a) the probability that the mean life of a random sample  of 9 such machines falls between 6.4 and 7.2

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{1}{\sqrt{9}}=0.333

We want this probability:

P(6.4

Part b

b) The value of x to the right of which 15% of the  means computed from random samples of size 9 would fall.

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.15   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.036. On this case P(Z<1.036)=0.85 and P(Z>1.036)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.036

And if we solve for a we got

a=7 +1.036*0.333=7.345

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

8 0
2 years ago
The line with the equation 4/5x +1/3y=1 is graphed one the xy-plane. What is the x-coordinate of the x-intercept of the line?
leva [86]

Answer:

x = 4/5

Step-by-step explanation:

The x-intercept looks like (x, 0); the coordinate 0 indicates that the point lies on the x-axis.  If we start with 4/5x + 1/3 y= 1 and let y = 0, we will get an equation for the x-intercept:

(4/5)x + (1/3)(0) =1

Then 4/5x = 1, and (5/4)(4/5)x = (1)(4/5).

Thus, x = 4/5, and the x-intercept is (4/5, 0).

4 0
2 years ago
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