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tatuchka [14]
2 years ago
11

Fertiliser is sold in 100kg bags labelled with the amount of nitrogen (N), phosphoric acid (P2O5), and potash (K2O) present. The

mixture of these nutrients varies from one type of fertiliser to the next. 1 bag of Vigoro Ultra Turf fertiliser contains 29kg of nitrogen, 3kg of phosphoric acid, and 4kg of potash. 1 bag of Parkers Premium Starter fertiliser contains 18kg of nitrogen, 25kg of phosphoric acid, and 6kg of potash. How many bags of Vigoro Ultra Turf and Parkers Premium Starter would you require in order to make a fertiliser mixture containing 217kg of nitrogen, 115kg of phosphoric acid, and 44kg of potash
Mathematics
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

Step-by-step explanation:

Let's first list the percentage compositions of each fertilizer type:

<u>Vigoro Ultra Turf:</u>

Nitrogen (N) = 29 kg

Phosphoric Acid (P2O5) = 3 kg

Potash (K2O) = 4 kg

<u>Parkers Premium</u>

Nitrogen (N) = 18 kg

Phosphoric Acid (P2O5) = 25 kg

Potash (K2O) = 6 kg

We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:

x = Vigoro Ultra turf (one bag)

y = Parkers Premium (one bag)

29x + 18y = 217   -Equation 1

3x + 25y = 115     -Equation 2

4x + 6y = 44        -Equation 3

Solving for x and y, we get:

x = 5

y = 4

This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

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A toy store owner purchased 70 puppets for $1006. She sold them for $1412. How much profit did she make per puppet?
Marizza181 [45]

Answer:

5.80

Step-by-step explanation:

How much was the total profit

1412 -1006

406

She sold 70 puppets

The profit per puppet is the profit divided by the number of puppets

406/70

5.80

8 0
1 year ago
Is finding the value for the variable the only solution to real-world problems? Explain.
loris [4]

No. In many real-world scenarios, the variable is a value that is compared to other quantities. The value for the variable is used to find the quantities it is compared to.

5 0
1 year ago
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Choose the product. -7p 3(4p 2 + 3p - 1)
DIA [1.3K]

Answer:

14p -3

Step-by-step explanation:

-7p 3(4p 2+3p - 1)

3x4= 12p

3x3=9p

12+9= 21

21-7=14p

3x2=6

3x-3=-9

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hope this helps :)

7 0
1 year ago
The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

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4 0
2 years ago
a ball bounces from a height of 2 metres and returns to 80% of its previous height on each bounce. find the total distance trave
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We have 2+.8(2) + .8(.8(2)) + .8(.8(.8(2))) + ... = 

2( .8^0 + .8^1 + .8^2 + .8^3 + ... ) = 

2(.8^n -1) / (.8-1) . As n-->infinity, .8^n-->0 giving us 

<span>2(-1)/(-.2) = 2(5) = 10 meters.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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