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2 years ago

11

Fertiliser is sold in 100kg bags labelled with the amount of nitrogen (N), phosphoric acid (P2O5), and potash (K2O) present. The

mixture of these nutrients varies from one type of fertiliser to the next. 1 bag of Vigoro Ultra Turf fertiliser contains 29kg of nitrogen, 3kg of phosphoric acid, and 4kg of potash. 1 bag of Parkers Premium Starter fertiliser contains 18kg of nitrogen, 25kg of phosphoric acid, and 6kg of potash. How many bags of Vigoro Ultra Turf and Parkers Premium Starter would you require in order to make a fertiliser mixture containing 217kg of nitrogen, 115kg of phosphoric acid, and 44kg of potash

1 answer:

anzhelika [568]2 years ago

6 0

Answer:

We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

Step-by-step explanation:

Let's first list the percentage compositions of each fertilizer type:

<u>Vigoro Ultra Turf:</u>

Nitrogen (N) = 29 kg

Phosphoric Acid (P2O5) = 3 kg

Potash (K2O) = 4 kg

<u>Parkers Premium</u>

Nitrogen (N) = 18 kg

Phosphoric Acid (P2O5) = 25 kg

Potash (K2O) = 6 kg

We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:

x = Vigoro Ultra turf (one bag)

y = Parkers Premium (one bag)

29x + 18y = 217 -Equation 1

3x + 25y = 115 -Equation 2

4x + 6y = 44 -Equation 3

Solving for x and y, we get:

x = 5

y = 4

This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

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Answer:

The domain is (-∞ , ∞)

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Step-by-step explanation:

Here, we want to identify the domain of the linear function

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On if the domain is discrete or continuous, we can see that the domain is continuous.

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A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can

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Let $x = 1.66666...$ ....(1)

Multiply both sides of equation (1) by 10.

$10x = 1.666666....$ .... (2)

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1 year ago

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An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equ

kompoz [17]

Answer:

0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 800, \sigma = 40, n = 16, s = \frac{40}{\sqrt{16}} = 10$

Find the probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

This probability is the pvalue of Z when $X = 775$ . So

$Z = \frac{X - \mu}{s}$

$Z = \frac{775 - 800}{10}$

$Z = -2.5$

$Z = -2.5$ has a pvalue of 0.0062. So there is a 0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

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2 years ago

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yulyashka [42]

Answer:

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Step-by-step explanation:

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AlladinOne [14]

Answer:

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Step-by-step explanation:

Given

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Required

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if 1mm = 0.1cm

then

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4mm = 0.4 cm

This means that each row of beads is placed at 0.4 cm mark.

The distance between each row follows an arithmetic progression and it can be solved as follows;

$T_n = a + (n-1)d$

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n = ?? (number of rows)

Solving for n; we have the following;

$T_n = a + (n-1)d$ becomes

$20 = 0 + (n-1)0.4$

$20 = (n-1)0.4$

DIvide both sides by 0.4

$\frac{20}{0.4} = \frac{(n-1)0.4}{0.4}$

$50 = (n-1)$

$50 = n-1$

Add 1 to both sides

$50 + 1= n-1 + 1$

$n = 51$

Hence, the number of rows of beads is 51

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2 years ago