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Usimov [2.4K]
2 years ago
12

Orla and Eduardo each looked at a strand of their hair under a microscope and measured the diameter. Orla's strand was 0.005\,\t

ext{cm}0.005cm0, point, 005, start text, c, m, end text in diameter, and Eduardo's strand was 0.012\,\text{cm}0.012cm0, point, 012, start text, c, m, end text in diameter. How much greater was the diameter of Eduardo's hair?
Mathematics
3 answers:
Goryan [66]2 years ago
8 0

Answer:

0.007

Step-by-step explanation:

Artyom0805 [142]2 years ago
4 0

Answer:

30x2010x943

Step-by-step explanation:

219x29192

Guest1 year ago
0 0

answer:


0.007

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"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
Westkost [7]

Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

3 0
2 years ago
What weight of dry substance is in 150g of a 3% substance solution? What weight of an 8% solution can we have with the same weig
Pavlova-9 [17]
The answers are: 4.5 g and 56.25 g respectively.

Since the first type of measurement in this question is weight or mass, I'll suppose that the percentage concentration is % mass/mass. For that type of concentration measurement, just multiply the percentage by the total mass to get the mass of the wanted material.
So 150 g * 3% = 150 g * 0.03 = 4.5g

For the 8% solution with the same amount of dry substance, use the ratio of percentages, multiplied by the mass of the first solution to get the wanted amount of new solution:
3/8 * 150 g = 56.35 g
5 0
1 year ago
Cecily is comparing two checking accounts. Checking account A has a monthly fee of $16 and a per-check fee of $0.08, while check
Tpy6a [65]

Answer:

(1) 0.08x + 16

(2) 0.08x + 16=0.12x + 14

Step-by-step explanation:

Checking account A has a monthly fee of $16 and a per-check fee of $0.08

Per check fee is a constant rate that is 0.08

Let x represents the number of checks Cecily writes per month

1 check fee = 0.08

x checks fee = 0.08x

monthly fee is $16 , we add that as well

So total monthly fee charges for account A  is

0.08x + 16

checking account B has monthly fee of $14 and a per-check fee of $0.12.

1 check fee = 0.12

x checks fee = 0.12x

monthly fee is $14 , we add that as well

So total monthly fee charges for account B  is

0.12x + 14

(2) To find number of checks write per month for the accounts to charge the same in fees

WE set both expression , account A = account B

0.08x + 16=0.12x + 14

Subtract 0.12x on both sides

-0.04x + 16 = 14

Now subtract 16 on both sides

-0.04x = -2

Divide by -0.04 on both sides

So x= 50



7 0
2 years ago
A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints
Sliva [168]

Answer:

a)0.099834

b) 0

Step-by-step explanation:

To solve for this question we would be using , z.score formula.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.

a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.

Standard Deviation = √variance

= √0.16 = 0.4

Standard deviation = 0.4

Mean = 21.37

x = 20.857

z = (x-μ)/σ

z = 20.857 - 21.37/0.4

z = -1.2825

P-value from Z-Table:

P(x<20.857) = 0.099834

b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.

z score formula used = (x-μ)/σ/√n

x = 20.857

Standard deviation = 0.4

Mean = 21.37

n = 100

z = 20.857 - 21.37/0.4/√100

= 20.857 - 21.37/ 0.4/10

= 20.857 - 21.37/ 0.04

= -12.825

P-value from Z-Table:

P(x<20.857) = 0

c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.

5 0
2 years ago
The formula for the future value V (in dollars) of an investment earning simple interest is V=p+prt, where p (in dollars) is the
zhannawk [14.2K]

a)

V=p+prt

now we solve for P

V=P (1+rt)

Divide both sides by (1+rt)

P=V÷(1+rt)...answer

b)

P=V÷(1+rt)

P=3,000÷(1+0.06×5)

P=2,307.69

5 0
2 years ago
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