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Usimov [2.4K]
2 years ago
12

Orla and Eduardo each looked at a strand of their hair under a microscope and measured the diameter. Orla's strand was 0.005\,\t

ext{cm}0.005cm0, point, 005, start text, c, m, end text in diameter, and Eduardo's strand was 0.012\,\text{cm}0.012cm0, point, 012, start text, c, m, end text in diameter. How much greater was the diameter of Eduardo's hair?
Mathematics
3 answers:
Goryan [66]2 years ago
8 0

Answer:

0.007

Step-by-step explanation:

Artyom0805 [142]2 years ago
4 0

Answer:

30x2010x943

Step-by-step explanation:

219x29192

Guest1 year ago
0 0

answer:


0.007

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In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t
victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is   p =\frac{1}{5}

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5  

b

The mean is  \mu = 20

The standard deviation is \sigma=4

c

The probability, P =0.0002

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability Pe = 0.0003

The probabilities P \approx Pe

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

                  p =\frac{1}{5}

                    =0.2

The mean of this distribution is mathematical represented as

           \mu = np

substituting the value

         \mu = 100 * 0.2

             \mu = 20

The standard deviation is mathematically represented as

         \sigma = \sqrt{np (1-p)}

substituting the value

           = \sqrt{100 * 0,2 (1-0.2)}

           \sigma=4

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

               P=P(X \ge 34 )

By standardizing the normal approximation we have that

              P(X \ge 34) \approx P(Z \ge z)

Now z is mathematically evaluated as

               z = \frac{x-\mu}{\sigma }

Substituting values

             z = \frac{34-20}{4}

               =3.5

So  using the z table the P(Z \ge 3.5) is  0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small  So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

 

6 0
2 years ago
Lucia is making a 21.6 centimeter beaded string to hang in the window. She decides to put a green bead every 0.4 centimeters and
olasank [31]
21.6 ÷ 0.4 = 54 times for green
21.6 ÷ 0.6 = 36 times for purple

Together, 90 beads. Separately, 54 green and 36 purple.
3 0
2 years ago
Read 2 more answers
CALC 1: Spud's mom is going to make him a round birthday cake, and has asked for your help. Spud is a bit weird, and has already
Ratling [72]

Answer:

15.7 in  

Step-by-step explanation:

A slice of a round pie is a sector of a circle.

The perimeter of a slice is the arc length s plus twice the radius r.

P = s + 2r

s = rθ = r(16/360) = r/22.5. So,

16 = (r/22.5) + 2r = (r + 45r)/22.5 = 46r/22.5

16 × 22.5 = 46r

360 = 46r

r = 7.826  

D = 2r = 2 × 7.826 = 15.7 in

The diameter of the cake should be 15.7 in.

Check:

\begin{array}{rcl}P & = & s + 2r\\& = & \dfrac{r}{22.5} + 2r\\\\16 & = & \dfrac{7.826}{22.5} + 2 \times 7.826\\\\16 & = & 0.35 + 15.65\\16 & = & 16.00\\\end{array}

It checks.

 

6 0
2 years ago
There is a number between 100 and 115, such that if you find the sum of the cubes of the digits, subtract this sum from 99, divi
balandron [24]
114

1^3 + 1^3 + 4^3 = 1 + 1 + 64 = 66
99 - 66 = 33
33/3 = 11
1 + 1 = 2

I am not sure of the exact way to solve this....I just did it by trial and error
7 0
2 years ago
A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. Each
Jobisdone [24]

Answer:

your... syllabus is different from mine....

Step-by-step explanation:

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2 years ago
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