There are 81 band members. :-)
4 rows of 20 = 80 ... with one left over = 80 + 1 (81)
6 rows of 13 = 78 ... with three left over = 78 + 3 (81)
7 rows of 11 = 77 ... with four left over = 77 + 4 (81)
Answer:
Step-by-step explanation:
Consider the given matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B is
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is given that
![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
On comparing corresponding elements of both matrices, we get
Therefore, the required values are .
Answer:
1/2 (1 half)
Step-by-step explanation:
The number of different sandwiches is calculated multiplying all of the possibilities for each material used:
rye or white bread: 2 options
ham or turkey: 2 options
cheese or no cheese: 2 options
So the number of different sandwiches that can be made is 2*2*2 = 8.
From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.
So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).
The probability is 10/12. If you need it as a decimal, it should be about 8.3%
First, list the numbers from smallest to greatest:
12, 15, 18, 20, 23, 23, 28
Median is the middle number of the list—20.
