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2 years ago

6

Victoria and her friends are going on a road trip that is 632.64 miles long. If they have 32.3 miles until their destination, ho

w far have they already traveled? Answer in decimal form.

1 answer:

scoray [572]2 years ago

5 0

600.34 All you need to do is subtract and that will be your answer.

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John and Belinda played a nine holes of golf. John's score was 10 less than two times Belinda's score. If Johns score was 54 str

polet [3.4K]

Answer:

Belinda's score is 32 strokes.

Step-by-step explanation:

Let the score of John be "x" and Belinda be "y".

It is given that, in the game of golf, John's score was 10 less than two times Belinda's score.

Also, John's score is 54 strokes.

The above equation can be written as ;

$x = 2(y) -10$

Here, x = 54,

$54 = 2(y) -10$

$64 = 2(y)$

$y = 32$

Thus, Belinda's score is 32 strokes.

6 0

2 years ago

Find the area, circumference =6pi yd

vitfil [10]

Circumference = 2πr

Given that circumference 0s 6π, find radius:
2πr = 6π
r = 6π ÷ 2π = 3

Now that we know that the radius is 3 yard, find area:
Area = πr²
Area = π(3)²
Area = 9π = 28.27 yd²

Answer: 28.27 yd²

7 0

2 years ago

2.314 divided by 1.3

kirza4 [7]

1.78 is the correct answer.

5 0

2 years ago

1. Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1,

zzz [600]

Answer:

Step-by-step explanation:

Given that Miguel is playing a game

The box contains 4 chips, 2 with number 1, and other two differntly numbered as 3 and 5.

OUt of these 4, 2 chips are drawn

P(drawing same number) = 2C2/4C2 = $\frac{1}{6}$

Prob (drawing differnt numbers) = 1-1/6 = $\frac{5}{6}$

Hence prob of winning 2 dollars = $\frac{1}{6}$

Prob of losing 1 dollar = $\frac{5}{6}$

b) Expected value = sum of prob x amount won

= $\frac{1}{6}2+\frac{5}{6}(-1)=-\frac{1}{2}$

c) Miguel can expect to lose 1/2 dollars for every game he plays

d) If it is to be a fair game expected value =0

i.e. let the amount assigned be s

Then $\frac{1}{6}s-\frac{5}{6}=0\\s=5$

6 0

2 years ago

Read 2 more answers

An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)

erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

18-20 Not 18-20 Total

Male 0.23 0.35 0.58

Female 0.16 0.26 0.42

Total 0.39 0.61 1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) = 0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0

2 years ago