The response time includes the round-trip signal time plus the robot's travel time.
59 min = 2*(9.5 min) +travel time
59 min -2*(9.5 min) = travel time = 40 min
The speed is distance / travel time
speed = (52.8 m)/(40 min) = 1.32 m/min
The robot's average speed was 1.32 meters per minute.
(I) Alpha+Beta= 2
Alpha-Beta= √D/|a|= √10
Alpha^2 - Beta^2
=(Alpha+Beta) (Alpha-Beta)
= 2* √10
= 2√10
Answer:
A. (x, y) → (x,-y), (x, y) → (x + 1, y + 1)
Step-by-step explanation:
Plot points B, C and D on the coordinate plane (blue points in attached diagram).
1 transformation is reflection across the x-axis with the rule
(x,y)→(x,-y)
and it maps these points to
- B(-3,0)→B'(-3,0)
- C(2,-1)→C'(2,1)
- D(-1,2)→D'(-1,-2)
These image points are marked in green in attached diagram.
2 transformation is translation 1 unit to the right and 1 unit up with the rule
(x,y)→(x+1,y+1)
and it maps previous image points to
- B'(-3,0)→B''(-2,1)
- C'(2,1)→C''(3,2)
- D'(-1,-2)→D''(0,-1)
Answer:

Step-by-step explanation:
The vertical displacement function is
, where
is measured in meters and
in seconds. Ball hits the ground when
. That is:

Whose roots can be found by using the General Formula for Second-Order Polynomials:

Solutions of this polynomial are:

Only the first root is physically consistent.
<h3>
Answer: D. g(x) = f(x)+4</h3>
The graph shows f(x) to have a y intercept at -1, which is where the diagonal line crosses the y axis. We want the y intercept to move to 3. So we must add 4 to the old y intercept to get the new y intercept.
We do this with every single point on f(x) to get g(x) = f(x)+4. This shifts the graph up 4 units.