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1 year ago

Paula has a dog that weighs 3 times as much as Carla's dog

Mathematics

1 answer:

ivanzaharov [21]1 year ago

4 0

Answer:

The weight of Paula's dog is 36 pounds.

Step-by-step explanation:

SO we would draw one box for the weight of Carla's dog. Then we would draw 3 boxes for the weight of Paula's dog.

To find how much does Paula's dog weigh we divide the total weight of the dogs by the total number of boxes.

So then you would calculate 48 divided by 4.

The weight of Carla's dog is 12 pounds.

Therefore the weight of Paula's dog is 3x12=3x10+3x2=30+6=36 pounds.

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A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What

MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* Lets explain how to solve the problem

- A drawing that shows a real object with accurate sizes reduced or

enlarged by a certain amount called the scale

- Drawing scale is a ratio between the drawing length and the

actual length

- To find the actual dimensions from the drawing dimensions use the

scale drawing

* Lets solve the problem

- A map of a rectangular park has a length of 4 inches and a width

of 6 inches

∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

- The scale of the map is 1 inch foe every 30 miles

∴ The scale drawing is 1 : 30

- To find the actual area find the actual dimensions

∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

- By using cross multiplication

∴ 1 : 30

4 : actual length

6 : actual width

∴ Actual length = (4 × 30)/1 = 120

∴ Actual length = 120 miles

∴ Actual width = (6 × 30)/1 = 180

∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

5 0

2 years ago

Which graph shows a function whose inverse is also a function? On a coordinate plane, two curved graphs are shown. f (x) sharply

sertanlavr [38]

Answer:

Step-by-step explanation:

Just took the quiz on edgenuity

6 0

2 years ago

What is the length of segment BD? Round your answer to the nearest hundredth. triangles ABC and ABD in which the triangles share

hichkok12 [17]

Answer:

BD = 4.99 units

Step-by-step explanation:

Consider the triangle ABD only.

The angle formed is 31 degrees which occurs between two sides that are AD and BC.

We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.

Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD

Using formula for tanθ

tanθ = Perpendicular/Base

tan31 = 3/BD

0.601 = 3/BD

BD = 3/0.601

BD = 4.99 units

6 0

2 years ago

-3^(-x)-6=-3^x+10 Solve the equation below for x by graphing plz

vitfil [10]

To graph it, just graph $y=-3^{-x}-6$ and $y=-3^x+10$ and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
$3^{-x}+6=3^x-10$
multiply both sides by $3^x$
$3^0+6(3^x)=3^{2x}-10(3^x)$
$1+6(3^x)=3^{2x}-10(3^x)$
minus 1 from both sides and minus 6(3^x) from both sides
$0=3^{2x}-16(3^x)-1$
use u subsitution
$u=3^x$
we can rewrite it as
$0=u^2-16u-1$
now factor
I mean use quadratic formula
for $ax^2+bx+c=0$ $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$
so for 0=u^2-16u-1, a=1, b=-16, c=-1
$u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}$
$u=8+/-\sqrt{65}$
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
$u=8+\sqrt{65}=3^x$
$8+\sqrt{65}=3^x$
if you take the log base 3 of both sides you get
$log_3(8+\sqrt{65})=x$
if you use ln then
$ln(8+\sqrt{65})=xln(3)$
then
$\frac{ln(8+\sqrt{65})}{ln(3)}=x$