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poizon [28]
2 years ago
11

How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)

Mathematics
1 answer:
olga55 [171]2 years ago
6 0

Answer:

840 ( D )

Step-by-step explanation:

GIVEN DIGITS : 1,2,3,4,5,6,7,8  

Number of odd numbers = 4

Number of even numbers = 4

therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )

Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2

8*7*6*5 = 1680 / 2 =  840 ways

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1 year ago
Adita has two options for how to invest $1,000. Plan A: Put the $1,000 in an account that pays $100 per year. Plan B: Put the $1
cluponka [151]

Answer:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year  (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

The correct answer is Plan A will be worth more than plan B after two years.

Step-by-step explanation:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year  (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

3 0
1 year ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

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Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

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7 0
2 years ago
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elixir [45]

Answer:

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1 year ago
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