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2 years ago

How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)

Mathematics

1 answer:

olga55 [171]2 years ago

6 0

Answer:

840 ( D )

Step-by-step explanation:

GIVEN DIGITS : 1,2,3,4,5,6,7,8

Number of odd numbers = 4

Number of even numbers = 4

therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )

Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2

8*7*6*5 = 1680 / 2 = 840 ways

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Select all of the following points that lie on the graph of f(x) = 7 - 3x.

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The points that lie on the graph of f(x) = 7 - 3 x, are (-1 , 10) , (2 , 1)

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Step-by-step explanation:

To prove that a point lies on the graph of a line

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∵ f(x) = y

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∵ x = -1 and y = 10

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∵ The left hand side is equal the right hand side

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∵ x = 2 and y = 1

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∴ 7 = 7 - 0

∴ 7 = 7

∵ The left hand side is equal the right hand side

∴ Point (0 , 7) lies on the graph of the line

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Learn more:

You can learn more about the linear equation in brainly.com/question/4326955

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