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kondaur [170]
2 years ago
14

A land surveyor places two stakes 500 ft apart and creates a perpendicular to the line that connects these two stakes. He needs

to place a third stake 100 ft away that is equidistant to the two original stakes. To apply the Perpendicular Bisector Theorem, the land surveyor would need to identify
A. a line parallel to the line connecting the two stakes

B. a line that is parallel to the perpendicular line

C. the midpoint along the line connecting the two stakes

D. the midpoint along any line that is perpendicular to the line connecting the two stakes
Mathematics
2 answers:
cupoosta [38]2 years ago
8 0

Answer:
We will choose the last option is correct.
Step-by-step explanation:
A land surveyor places two stakes 500 ft apart and locates the midpoint between the stakes.
From the midpoint, he needs to place another stake 100 ft away that is equidistant to the two original stakes.  
Therefore, to apply the Perpendicular Bisector Theorem, the land surveyor would have to identify a line that is "perpendicular to the line connecting the two stakes and going through the midpoint of the two stakes".
Therefore we will choose the last option is correct. (Answer)

viktelen [127]2 years ago
8 0

Answer:

D

Step-by-step explanation:

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A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain
svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55

The mean of this distribution is:

\mu=np=10*0.6=6

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8

The probability of having between 4 and 8 customers choosing the oversize version is:

P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328

7 0
2 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
2 years ago
Triangle ABC and triangle CDE are similar right triangles. Which proportion can be used to show that the slope of AC is equal to
shusha [124]

Answer:

Option C is the correct option.

Step-by-step explanation:

Considering the triangle ABC, the slope of the line CA is given by \frac{AB}{BC} = \frac{6 - 3}{-3 - (- 1)}

Again, considering the triangle CDE, the slope of the line EC is given by

\frac{CD}{DE} = \frac{3 - (- 3)}{- 1 - 3 }

Since CA and EC represents the same straight line so, we can write

\frac{6 - 3}{-3 - (- 1)} = \frac{3 - (- 3)}{- 1 - 3 }

Therefore, option C is the correct option. (Answer)

8 0
2 years ago
what is the simplified form of the following expression? Assume x is greater than or equal to 0 and y is greater than or equal t
yarga [219]

the given expression is :

2(4√16x) - 2(4√2y) + 34√81x - 4(4√32y)

⇒ 8(√16x) - 8(√2y) + 34√81x - 16√32y  

⇒8×4√x - 8√2y + 34×9√x - 16√16×2y     [∵ √16 = 4 and √81 = 9]

⇒32√x - 8√2y + 306√x - 16×4√2y

⇒(32√x + 306√x) - 8√2y  - 16×4√2y      

⇒338√x -72√2y

4 0
2 years ago
Read 2 more answers
The finances of a group of pet owners were analyzed to determine how much they were spending on their pet(s) each year. A graph
kvv77 [185]

Answer:

Option D.

Step-by-step explanation:

In the given graph x-axis represents the number of owners and y-axis represents yearly cost of pets, in hundreds.

It is given that the graph passes through the points (1,15), (3,7) and (10,0).

We need to check whether (4.5, 6) is a realistic solution for the function or not. (4.5,6) point represents

Number of owners = 4.5

yearly cost of pets = 6

It is realistic that owners spend $600 a year on their pet(s).

Number of owners can not be a fraction value. So, it is not realistic to have 4.5 owners.

Therefore, the correct option is D.

3 0
2 years ago
Read 2 more answers
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