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kondaur [170]
2 years ago
14

A land surveyor places two stakes 500 ft apart and creates a perpendicular to the line that connects these two stakes. He needs

to place a third stake 100 ft away that is equidistant to the two original stakes. To apply the Perpendicular Bisector Theorem, the land surveyor would need to identify
A. a line parallel to the line connecting the two stakes

B. a line that is parallel to the perpendicular line

C. the midpoint along the line connecting the two stakes

D. the midpoint along any line that is perpendicular to the line connecting the two stakes
Mathematics
2 answers:
cupoosta [38]2 years ago
8 0

Answer:
We will choose the last option is correct.
Step-by-step explanation:
A land surveyor places two stakes 500 ft apart and locates the midpoint between the stakes.
From the midpoint, he needs to place another stake 100 ft away that is equidistant to the two original stakes.  
Therefore, to apply the Perpendicular Bisector Theorem, the land surveyor would have to identify a line that is "perpendicular to the line connecting the two stakes and going through the midpoint of the two stakes".
Therefore we will choose the last option is correct. (Answer)

viktelen [127]2 years ago
8 0

Answer:

D

Step-by-step explanation:

You might be interested in
It is believed that as many as 23% of adults over 50 never graduated from high school. We wish to see if this percentage is the
JulijaS [17]

Answer:

1)  n=48  

2) n=298

3) n=426

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\hat p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Part 1

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.10 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:  

n=\frac{0.23(1-0.23)}{(\frac{0.1}{1.64})^2}=47.63  

And rounded up we have that n=48  

Part 2

The margin of error on this case changes to 0.04 so if we use the same formula but changing the value for ME we got:

n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.64})^2}=297.7  

And rounded up we have that n=298  

Part 3

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:  

n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.96})^2}=425.22  

And rounded up we have that n=426  

3 0
2 years ago
renu purchased an air conditioner for rs 40500 including 8% VAT. what was the price before including VAT?
jekas [21]

Answer:

₹ 37500

Step-by-step explanation:

Let the price before VAT be ₹x.

\therefore \: x + 8 \% \: of \: x = 40500 \\  \therefore \: x +0.08x = 40500 \\  \therefore \: 1.08x  = 40500 \\  \therefore \: x =  \frac{40500}{1.08}  \\ \huge  \red{ \boxed{ \therefore \: x = Rs.  \: 37,500}}

Hence the price before including VAT of air conditioner was ₹ 37,500.

7 0
2 years ago
Miss Croft made snack bags for the picnic that contain three types of snacks: packages of crackers, packages of cookies, and can
jek_recluse [69]

Answer: $1.25

Step-by-step explanation:

Let the cost of cracker be a.

Let the cost of cookies be b.

Let the cost of candy bars be c.

From the question,

6a + 6b + 6c = $21

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

To solve this, we first pick any two pairs of equation. This will be:

6a + 6b + 6c = $21 ....... i

8a + 5b + 10c = $26 ....... ii

Multiply equation i by 8

Multiply equation ii by 6

48a + 48b + 48c = $168 ....... iii

48a + 30b + 60c = $156 ....... iv

Subtract equation iv from iii

18b - 12c = 12

We then pick another two pairs

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

Multiply equation i by 5

Multiply equation ii by 8

40a + 25b + 50c = $130

40a + 32b + 56c = $148

Subtract the equations

-7b - 6c = -18

Then, solve the new equations formed

18b - 12c = 12 ....... v

-7b - 6c = -18 ....... vi

Multiply equation i by -7

Multiply equation ii by 18

-126b + 84c = -84

-126b - 108c = -324

Subtract the equations

192c = 240

c = 240/129

c = $1.25

From equation v, put the value of c

18b - 12c = 12

18b - 12($1.25) = 12

18b - $15 = $12

18b = $27

b = $27/18

b = $1.5

Since,

6a + 6b + 6c = $21

6a + 6($1.5) + 6($1.25) = $21

6a + $9 + $7.5 = $21

6a + $16.5 = $21

6a = $21 - $16.5

6a = $4.5

a = $4.5/6

a = $0.75

One candy bar cost $1.25

6 0
2 years ago
Which system of equations below has no solution? A. y = 4x + 5 and y = 4x – 5 B. y = 4x + 5 and 2y = 8x + 10 C. y = 4x + 5 and y
Stels [109]

Answer: A  y=4x -5 and y=4x+5

Step-by-step explanation:

They have no solutions because they have the same slopes but different y intercepts. That works with any equation.

8 0
2 years ago
14. A $40,000 loan at 4% dated June 10 is due to be paid on October 11. Calculate the amount of interest (assume ordinary intere
Allisa [31]
D) $546.67

Hope this helped!
5 0
2 years ago
Read 2 more answers
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