Which represents the solution to the absolute value equation? 5|2x-4|+1=11
1 answer:
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Answer:
We have to determine the graph of the given inequality as:
on solving this equation we get:
Since we know that:
Now we know that when the value of:
Also for the value other than -1 the function being a quadratic function will always give a non-zero positive value.
Hence, range of the function in intervals could be written as:
(-∞,-1)∪(-1,∞).
Hence, the graph of the function will be the whole of the number line with a open circle on -1.
Answer:
Step-by-step explanation:
The following is the logarithm quotient rule:
Plugging in the values we have above gives us the following:
For x-intercepts "b" and "c", a quadratic can be written as
y = a(x -b)(x -c)
You know the x-intercepts, so you can write the equation as
y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices
Substituting (x, y) = (-1, 2), you have
2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
-2/4 = a = -1/2 . . . . . corresponds to the third answer choice
The appropriate selection is
y = -1/2 (x + 2)(x - 3)
y = a(x -b)(x -c)
You know the x-intercepts, so you can write the equation as
y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices
Substituting (x, y) = (-1, 2), you have
2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
-2/4 = a = -1/2 . . . . . corresponds to the third answer choice
The appropriate selection is
y = -1/2 (x + 2)(x - 3)