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GREYUIT [131]
2 years ago
15

In a USA TODAY/Gallup Poll, respondents favored Barack Obama over Mitt Romney in terms of likeability, 61% to 32% (Los Angeles T

imes, July 28, 2012).a. What percentage of respondents favored neither Obama nor Romney in terms of likeability?Percentage of respondents b. For a given survey of 500, how many more respondents favored Obama than Romney?Number of respondents
Mathematics
1 answer:
dybincka [34]2 years ago
5 0

Answer:

a) percentage of respondents that favored neither Obama nor Romney in terms of likeability = 7%

b) For a given survey of 500, the number of respondents that favored Obama than Romney is 145.

Step-by-step explanation:

Given that none of those surveyed can favour the two candidates at the same time,

n(Universal set) = n(U) = 100%

n(Obama) = n(O) = 61%

n(Romney) = n(R) = 32%

n(That favour Obama and Romney) = n(O n R) = 0%

To calculate for the number that favour neither of the candidates

n(O' n R')

n(U) = n(O) + n(R) + n(O n R) + n(O' n R')

100 = 61 + 32 + 0 + n(O' n R')

n(O' n R') = 100 - 93 = 7%

b) For a given survey of 500, how many more respondents favored Obama than Romney?

Number of those surveyed that favour Obama = 61% of 500 = 305

Number of those surveyed that favour Romney = 32% of 500 = 160

Difference = 305 - 160 = 145

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Math Question: Your Team is given a bag containing a set of colored blocks or counters. The bag contains 5 yellow, 1 red, 6 green, and 8 blue blocks. If you were to reach into the bag and select one block without looking what is the probability of selecting a yellow block and the probability of selecting a green
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The ball bearing have volumes of 1.6cm cube and 5.4cm cube . Find the ratio of their surface area.
Korvikt [17]

Answer:

  4/9

Step-by-step explanation:

The scale factor for the linear dimensions of the ball bearings will be the cube root of the volume scale factor:

  k = ∛(1.6/5.4) = 2/3

Then the scale factor for the areas will be the square of this scale factor:

  ratio of surface area = (2/3)² = 4/9

_____

The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.

Similarly, volume is the product of three linear dimensions, so its scale factor is the cube of the linear dimension scale factor.

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2 years ago
A train station has installed a system for determining whether bags contain explosives. It has a 95% chance of correctly identif
astraxan [27]

Answer:

a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)

=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363

hence  probability that it actually contains explosives given identified as containing explosives)

=(10/(4*106))*0.95/0.005002363=0.000475

b)

let probability of correctly identifying a bag without explosives be a

hence a =0.99999763 ~ 99.999763%

c)

No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,

3 0
2 years ago
Brenda is rolling a six-sided die and flipping a coin. Complete each of the following sentences regarding the probabilities invo
sveta [45]
So for number there are 6 possible outcomes nad 5 is one of them so 1/6
He next one there are 2 outcomes and heads is 1 outcome so 1/2
For the next one you have to multiply them together so you get 1/12
And the events are independent because whatever you roll on the die won’t affect the coin(it actually does on a very small scale but I don’t think you go into that much detail for high school maths)
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2 years ago
Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi
Kay [80]

Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}

Now, we know the following identities:

sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}

Now, the values are:

sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}

Sine value is positive and cos, tan values are negative.

It can be clearly observed that \theta is in 2nd quadrant.

2nd quadrant means, the value of x will be negative and y will be positive.

Let us have a look at the value of tan\theta:

tan\theta  = \dfrac{Perpendicular}{Base}\\OR\\tan\theta  = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

8 0
2 years ago
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