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2 years ago

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stumpy the skeleton goes for a bike ride every night in the cemetery. He rides 1/2 way around the cemetery and stops. Stumpy the

n bikes 3/4 of the way around before stopping again. he finishes his ride by biking another 3/8. how far around the cemetery does stumpy bike?

1 answer:

marin [14]2 years ago

4 0

He bikes 13/8 of the cemetery

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Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

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1 year ago

Use the distributive property to solve the equation 4x/5-x=x/10-9/2

Oksana_A [137]

Answer:

$\Huge\boxed {x = 15}$

Step-by-step explanation:

⟾Collect like terms

8x - 10x = x - 45

⟾Move the variable to the left

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⟾Collect like terms again

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⟾ x = 45 ÷ 3

x = 15.

Hope it's helps you

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lukranit [14]

Answer:

The length of the remaining piece of thread is $\frac{1}{16}.$

Step-by-step explanation:

Given:

A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long.

Now, to find the length of the remaining piece of thread.

Total thread = $\frac{9}{16} \ inch.$

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Now, to get the length of the remaining piece of thread by subtracting tailor cuts a piece of thread from the total thread:

$\frac{9}{16} -\frac{1}{2} \\\\=\frac{9-8}{16} \\\\=\frac{1}{16}$

Therefore, the length of the remaining piece of thread is $\frac{1}{16}.$

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