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2 years ago

Every time x increases by 1,y decreases by 3,and when x is -6,yis-3.which function models the realation ship between x and y?

Mathematics

2 answers:

Levart [38]2 years ago

5 0

I think that it would be B because -6x-3 seems to follow the rules given here.

oksian1 [2.3K]2 years ago

4 0

Answer:

D. $y=-3x-21$

Step-by-step explanation:

We have been given that every time x increases by 1,y decreases by 3. This means that slope of our given line is negative 3.

We will use slope-intercept form of equation to find the required function.

$y=mx+b$ , where,

m = Slope of line,

b= The y-intercept.

Upon substituting $m=-3$ and $x=-6$ and $y=-3$ in slope-intercept form of equation, we will get,

$-3=-3\times -6+b$

$-3=18+b$

$-3-18=18-18+b$

$-21=b$

Upon substituting $m=-3$ and $b=-21$ in slope-intercept form of equation, we will get our required equation as:

$y=-3x-21$

Therefore, option D is the correct choice.

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2 years ago

According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1

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b) 0.00%

c) 1.54%

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If 1100 Americans are sampled, then the sample size is $n=1100$ .

The mean of the distribution is $\mu=np$ .

This means $\mu=1100\times 0.10=110$

The standard deviation is $\sigma=\sqrt{npq}$

We substitute the values to get:

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a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: $P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)$

We now convert to Z-scores to get:

$P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\$

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)$

We convert to z-scores:

$P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48$

From the normal distribution, P(z>164.5)=0

c) First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\le88)=P(X\:$

We convert to z-scores:

$P(X\:$

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

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