Answer:
C. The United States maintains military forces in South Korea, a close ally.
Step-by-step explanation:
Solution:

We have to find the remainder when f(x) is divided by 
x²-1=0
x=
So, remainder is 13 and -13.
Answer:
How far should he ride on each of the four days to reach his goal?
1st day:
miles
2nd day:
miles
3rd day:
miles
4th day:
miles
Step-by-step explanation: As the problem says,
is the number of miles he rides on the first day. Let's start off with that.
1st day:
miles
He want to ride 1.5 times as far as he rode the day before... no 1.5 more, but 1.5 <em>times</em> as far as he rode the day before; you would multiply 1.5 with the previous day's length.
2nd day: 
Then you multiply
to
to get the third day's.
3rd day: 
4th day: 
----------------------------
Phew! Gavin wants to ride a total of 65 miles over these four days, so if Gavin added all the miles of the four days, he should get 65...
1st+2nd+3rd+4th=65




Yes! Now that we've got the hard part done... substitute 8 for ever single
.
1st day:
miles
2nd day:
miles
3rd day:
miles
4th day:
miles
-------------------------
Checking my answer:
Just add the miles!


✓
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Hope that helps! :D
Assuming that am supposed to calculate the the mean absolute deviation of
1,2,3,4,5,6,7
mean absolute deviation is calculated by first calculating the mean;
(1+2+3+4+5+6+7) =28/7
= 4
Then, find the absolute value (the difference between each value in the data and the mean) (x-μ)
= -3,-2,-1,0,1,2,3
Absolute values= 3,2,1,0,1,2,3
Then we find the mean of the values,
3+2+1+0+1+2+3 = 12
= 12/7
= 1.7143
Therefore, the mean is 4, and the Mean absolute deviation is 1.7143
Answer:
6 knots
Step-by-step explanation:
Let the speed be v knots
then time taken to cover 500 M = 500 / v hrs
fuel consumption /hr = 216 + 0.5v^3
let F be the fuel consumption for trip
= [500/v][216 + 0.5v^3]
= 500[216/v + 0.5v^2]
dF/dv = 500[ - 216/v^2 + v]
d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve
so setting dF/dv will give a minima
500[ -216/v^2 + v] = 0
or v = 216/v^2
or v^3 = 216
solving, we get v = [216]^(1/3) = 6 knots