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Harlamova29_29 [7]
1 year ago
12

If 25^x+1 = 125/5^x find the value of x

Mathematics
1 answer:
storchak [24]1 year ago
8 0
  • Answer:

<em>x =1/3</em>

  • Step-by-step explanation:

<em>25ˣ⁺¹ = 125/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³ : 5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³⁻ˣ</em>

<em>2(x + 1) = 3 - x</em>

<em>2x + 2 = 3 - x</em>

<em>2x + x = 3 - 2</em>

<em>3x = 1</em>

<em>x = 1/3</em>

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Leo is constructing a tangent line from point Q to circle P. What is his next step?
artcher [175]

Answer:

Mark the point of intersection S of circles R and P, and construct line QS.

Step-by-step explanation:

In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.

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2 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

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Answer:

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Step-by-step explanation:

If Jamal cuts the right circular cylinder anywhere but its extremities, the resulting shapes on both pieces will be an ellipse.  

If he cuts precisely in a perpendicular way in relation to the ends, he will then form two new right circular cylinders, then the ellipses obtained would be circles.

If Jamal cuts the right circular cylinder lengthwise, going from one end to the other, even if it's not perpendicular to the base, he will obtain a rectangular shape.

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